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It is common way to replace a pattern match with string, but I need to replace all sub-strings which match pattern from text to be matched as another pattern match, is it possible?

For example, is it possible to replace all matches to [0-9]{2}'[0-9]{2} which represent all strings like 99'99 or 85'55

To this [0-9]{2}.[0-9]{2} which represent all strings like 99.99 or 85.55

Is it possible? How to do this kind of replacements? or I have to handle it manually through matches in for each loop?

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    Do you mean the capturing groups: ([0-9]{2})'([0-9]{2}) > $1.$2? Commented Mar 17, 2016 at 16:23
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    @WiktorStribiżew: If a Guru like you gives correct answer in comments how are noobs like me going to get chance to solve some simpler problems and rise up the ranks ? Commented Mar 17, 2016 at 16:30
  • @WiktorStribiżew: Good point :) Commented Mar 17, 2016 at 16:31
  • @WiktorStribiżew: The current comment is the edited one asking for clarification. The first one was rather a direct demo of solution. Correct me if am wrong. If you had posted it as solution there wasn't a problem at all. But posting a correct solution in comment gives other users who might not have solution, copy yours. And if a genuine users posts his solution which is similar ( it's regex so most are similar ) it will be down voted considering it as copying answers. Commented Mar 17, 2016 at 16:51
  • If your question is to replace sub-strings like 99'99 to 99.99, then it is as simple as to replace ' with .. Otherwise, please edit your post with another proper example. Commented Mar 17, 2016 at 18:04

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Use the Regex.Replace() instance function along with Regex capture groups like this:

var regex = new Regex("([0-9]{2})'([0-9]{2})");
string result = regex.Replace(input, "$1.$2");

More details about capture groups can be found here.

Also, check out this answer. It shows how to use 'named' groups which might help in future.

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So as I understand you, you have something like 99'99 or 85'55 and want this to be replaced by 99.99 or 85.55?

What you might look for are capture groups, i.e. find for a matching, catch this matching and put this to the result.

the RegEx here would be s/([0-9]{2})'([0-9]{2})/$1.$2/g

Explanation: ([0-9]{2}) the brackets declare the caption group. It means, whatever is captured in it, will be stored to a variable. These Variables are $1 and $2, because there were two capture groups.

When building the replacement string, just insert those variables and put the dot between them.

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5 Comments

It's dot not comma.
Why does your regex have replacement part in it ?
because the question asker asked how to do the replacement.
I don't mean to say why you are doing replacement. I mean replacement part won't be appearing in regex. It will be separate from regex. See the answer below.
I didn't see the C# tag at first and this question seemed to be a 'standard' RegEx question, so I provided a RegEx which solves the problem, checked it with perl (in this case, it does appears in the regex).

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