remove always last array in php

Question

i am trying to remove last array after i made an explode on this strings: Example 1

Adress1
Adress2
String1 : String2

Example 2

Adress1
Adress2
Adress3
String1 : String2

My idea was first to check if their is a match " : " in string(adrori) then the last array "String1 : String2" should be removed completely. No matther how much array counts would be counted.

Here is my code:

if (preg_match("/ : /", $adrori)) {
    $arr2 = explode("\n", $adrori);
    $adrori = array_pop($arr2);
    $adrori = implode("\n", $adrori);
}

thanks

I don't understand the examples. Can you please post the output for var_export($adrori); that corresponds to the examples? — VolkerK
– VolkerK, Commented Mar 7, 2016 at 11:28
Do you know that if the string contains “String1 : String2” in first line and “Adress3” in the last line, “Adress3” will be removed? — fusion3k
– fusion3k, Commented Mar 7, 2016 at 11:36
all addresses ends with String : String. Sometimes are two rows and sometimes more than two. But always appears at the end of String the following: ExampleString : ExampleString. So i am trying to remove always the last row with " : " at the end of string. — Erik
– Erik, Commented Mar 7, 2016 at 11:37

ksimka · Accepted Answer · 2016-03-07 11:29:41Z

1

array_pop changes its argument and returns the last element. So you should do it like this.

if (preg_match("/ : /", $adrori)) {
    $arr2 = explode("\n", $adrori);
    array_pop($arr2);
    $adrori = implode("\n", $arr2);
}

answered Mar 7, 2016 at 11:29

ksimka

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Comments

fusion3k · Accepted Answer · 2016-03-07 11:50:56Z

1

In your example, after removing last array item you re-implode it.

So, you can obtain desired result also using preg_replace, without exploding/imploding:

$adrori = trim( preg_replace( '/.+ : .+$/', '', $adrori ) );

or:

$adrori = preg_replace( '/\n.+ : .+$/', '', $adrori );

Pattern explanation:

\n  newline
.+  one or more characters
 :  space-colon-space
.+  one or more characters
$   end of string

edited Mar 7, 2016 at 11:50

answered Mar 7, 2016 at 11:44

fusion3k

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Comments

Indrajit · Accepted Answer · 2016-03-07 11:37:26Z

0

Try this out:

$a = array('a1','a:2');
$b = array_filter($a,function($value){
if(strpos($value, ':') === false){
  return $value;
 }
});
print_r($b);

answered Mar 7, 2016 at 11:37

Indrajit

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Comments

Erik · Accepted Answer · 2016-03-07 12:00:38Z

the example from @ksimka worked! Thank you so much people!

My mistake was to give variable to aray_pop.

Wrong:

 if (preg_match("/ : /", $adrori)) {
        $arr2 = explode("\n", $adrori);
        $adrori = array_pop($arr2);
        $adrori = implode("\n", $adrori);
    }

right:

 if (preg_match("/ : /", $adrori)) {
        $arr2 = explode("\n", $adrori);
        array_pop($arr2);
        $adrori = implode("\n", $adrori);
    }

Thank you

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