Write a function which takes a number represented as a String as an argument, for example "12345" or "4321432143214321" and returns the digits of that number in an array.
Your function should create an int[] array with one digit of your number per element.
Can someone please a hint as how I can approach this problem?
public int[] convertToArray(String str){
int array[] = new int[str.length()];
for(int i = 0; i < array.length; i++){
try{
array[i] = Integer.parseInt(str.substring(i,i+1));
}catch(NumberFormatException e){
e.printStackTrace();
array[i] = 0;
}
}
return array;
}
Just for fun, a Java 8 solution:
int[] result = input.codePoints().map(Character::getNumericValue).toArray();
int[] getStringAsArray(String input) {
int[] result = new int[input.length()];
for (int i=0; i < input.length(); ++i) {
result[i] = Character.getNumericValue(input.charAt(i));
}
return result;
}
Note that any character in the input string which is not a number will be converted to a negative value in the output int[] array, so your calling code should check for this.
