My professor is currently teaching the topic of Dynamic Memory Allocation along with pointers. I don't quite understand the following example:
#include <iostream>
#include <cstring>
#include <cstdlib>
using namespace std;
int main(void)
{
int i;
char * names[7]; // declare array of pointers to char
char temp[16];
// read in 7 names and dynamically allocate storage for each
for (i = 0; i < 7; i++)
{
cout << "Enter a name => ";
cin >> temp;
names[i] = new char[strlen(temp) + 1];
// copy the name to the newly allocated address
strcpy(names[i],temp);
}
// print out the names
for (i = 0; i < 7; i ++) cout << names[i] << endl;
// return the allocated memory for each name
for (i = 0; i < 7; i++) delete [] names[i];
return 0;
}
For the line that prints out the names, I don't understand how "names[i]" prints out the names. Shouldn't "names[i]" print out the pointers instead? Any help on this is greatly appreciated.
std::endlunless you need the extra stuff that it does.'\n'starts a new line.