Getting Php Curl Error

Question

I want to grab first 10 results of that any url i passed it to function as parameter ..and i want to make data scraper for some sites

Getting Syntax error when I print the result on screen syntax error on this line I don't why it giving me syntax error kindly help me....

print_r( $dse->crawl()->parse() );

<?php               
      class CURL_CRAWLER{
      public $url;
      public $request_type;
      public $data;
      public $post_params;

  function __construct($url = '' , $request_type = 'GET')
  {
     $this->url = $url;
     $this->request_type = $request_type;
     $this->data = '';
     $this->post_params = array();
   }
/**crawl a document **/
 function crawl()
   {
    $curl = curl_init( $this->url );
    curl_setopt($curl, CURLOPT_HEADER, false);
    curl_setopt($curl, CURLOPT_TIMEOUT, 60);
    curl_setopt($curl, CURLOPT_USERAGENT, 'cURL PHP');
    curl_setopt($curl, CURLOPT_RETURNTRANSFER, TRUE);
    $this->data = curl_exec($curl);
    curl_close($curl);
    return $this; //make it a chainable method
   }
/** Parse result data **/
   function parse(){
   $result = array();
   $count = 0;
   $dom = new DOMDocument;
   $dom->preserveWhiteSpace = false;
   $dom->loadHTML($this->data);
   $xpath = new DOMXPath($dom);
   $news = $xpath->query('//td[@bgcolor="#DDDDDD"]/table/tr[position()=2]/td[position()=2]');
   foreach( $news as $n){
       $result[] =   $n->nodeValue;
       $count++;
       if ($count >9)
           break; //we just need  10 results. Index starts from 0
   }
   return $result;
      }
    }
 error_reporting(0);
        $dse = new CURL_CRAWLER('http://www.dsebd.org/display_news.php');
    echo "<pre>";
    print_r( $dse-&gt;crawl()-&gt;parse() );
    echo "<pre>";

   ?>

i don't understand wat u want to say actually kindly elobrate — Muhammad Usman
– Muhammad Usman, Commented Jan 7, 2016 at 14:32
if the above code is exactly how your code looks like, the syntax error is that php opening tag is not at the beginning, it should be the first thing — n-dru
– n-dru, Commented Jan 7, 2016 at 14:34

n-dru · Accepted Answer · 2016-01-07 14:53:46Z

2

Your syntax error is that you should use explicit "greater than" sign instead of HTML entities > - server doesn't need those, it is not a browser that can render it correctly. Just change:

print_r( $dse-&gt;crawl()-&gt;parse() );
              ^^^^        ^^^^

to:

print_r( $dse->crawl()->parse() );

answered Jan 7, 2016 at 14:53

n-dru

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