Is there a simple way to create an initialized array?

Question

I want to create an int[n] array of unique numbers:

int[] result = new int[24];

for(int i = 0; i<24; i++)
    result[i] = 1;

return result;

Is there a shorter way to accomplish this. May be something like this:

return (from i in new int[24] 
        select 1).ToArray();

But not as ugly as this.

i.e. you want to create an array initialized with some number different from 0? — Paolo Tedesco
– Paolo Tedesco, Commented Aug 9, 2010 at 8:11
Did none of the answers on your other questions answer those? — Bobby
– Bobby, Commented Aug 9, 2010 at 8:11
for(int i = 0; i<24; i++) result[i] = 1; In this code you set all the numbers to 1. This is not unique but just initialized. — Yves M.
– Yves M., Commented Aug 9, 2010 at 8:14

Jon Skeet · Accepted Answer · 2010-08-09 08:10:57Z

11

I'm not sure in what way making them all "1" makes them unique, but this will do the equivalent to your code:

return Enumerable.Repeat(1, 24).ToArray();

answered Aug 9, 2010 at 8:10

Jon Skeet

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2 Comments

David Hedlund Over a year ago

+1 for flagging that this is only the equivalent to the example, not to what it seems like the OP is asking for. in that sense, it might be added that Enumerable.Range(0, 24).ToArray(); might be what OP is looking for, if we're allowed to assume a typo in both examples.

Cheng Chen Over a year ago

haha,just now I misunderstood OP's question and give the Enumerable.Range answer. He says "result[i] = 1" not "result[i] = i";

Martin Harris · Accepted Answer · 2010-08-09 08:11:47Z

5

The code you posted doesn't seem to match the title of the question, but this will do the same as your snippet:

Enumerable.Repeat(1, 24).ToArray()

answered Aug 9, 2010 at 8:11

Martin Harris

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1 Comment

al-bex Over a year ago

Sorry for my bad english. The question should be: Is there a simple way to create an array filled with a constant?

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