String format output

Question

Having a source program like below:

from string import Template
s=Template('$x,glorious $x!')
print s.substitute(x='slurm')
print s
print Template

and Output like below:

slurm,glorious slurm!
<string.Template object at 0x024955D0>
<class'string.Template'>

Why?The last outputs I can't understand.

because you are printing a string.Template instance and then just the class Template ... — Joran Beasley
– Joran Beasley, Commented Dec 9, 2015 at 6:50
Thanks.I make a mistake ,I think s.substitute will change original array.lol — M.r
– M.r, Commented Dec 9, 2015 at 7:08
@M.r No, substitute doesn't change the original Template, it returns a new string rendered from the template. — masnun
– masnun, Commented Dec 9, 2015 at 7:41

masnun · Accepted Answer · 2015-12-09 07:40:31Z

1

Here you are creating a template:

s=Template('$x,glorious $x!')

Now you are parsing the template, replacing x with slurm:

print s.substitute(x='slurm')

Please notice, the above call returns a new string which is what you want to store in a new variable if you need to use it somewhere else.

You are printing s which is a Template object:

print s

You are printing Template which is a class you imported:

print Template

So probably this is what you wanted:

from string import Template
s=Template('$x,glorious $x!')
result = s.substitute(x='slurm')
print result

answered Dec 9, 2015 at 7:40

masnun

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