bash: adding elements to array

Question

in this code i just save paths into array#1. This array works fine:

echo "Searching for *omd*-paths..."
cd /

# creating array#1
all_omd_paths=`find -type d -name omd`

Ok, but now i want to put specific paths into another array (array#2):

for path in $all_omd_paths
do
        if [[ $path == *"s"* ]]; then
            # fill array#2
            omd_sites_paths+=($path)
        fi
done

for path in $omd_sites_paths
do
    # wrong output
    echo $path
done

With the second for-loop i just get ONE path on output... But i know there are more saved in array#1. What s wrong with array#2? How do i fill it correctly?

Your creating array#1 is downright wrong. It doesn't create an array. And when accessing all array elements in bash, you need "${omd_site_paths[@]}". Moreover, the entire thing is not safe at all against whitespaces and special characters in paths. — 4ae1e1
– 4ae1e1, Commented Dec 4, 2015 at 9:45
Oh ok, thank you. Do you have a hint or keyword for getting the paths out of 'find'-command? — Basssprosse
– Basssprosse, Commented Dec 4, 2015 at 10:05
Use find -print0 and a while read loop. See BashFAQ/001: mywiki.wooledge.org/BashFAQ/… . Carefully replicate all the options to both commands! They are all vital in ensuring robustness. — 4ae1e1
– 4ae1e1, Commented Dec 4, 2015 at 10:08

Cyrus · Accepted Answer · 2015-12-04 09:45:36Z

1

If $omd_sites_paths is an array:

for path in ${omd_sites_paths[@]}

answered Dec 4, 2015 at 9:45

Cyrus

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