I have this table:
ID_Articulo ID_Componente Tipo Cantidad
1 5 2 1.5
5 3 1 3
1 6 1 6
2 3 1 3.5
6 8 2 4.2
8 9 1 2
I need to find the SUM of Cantidad field for a given ID_Articulo and Tipo=1. For instance, for ID_Articulo=1 should be 1.5*3 + 6 + 6*4.2*2 = 60.9.
The number to level (deep) are variable for each ID_Articulo.
Can this be donw with a SQL query? My database is SQL Server 2005.
Aditional info
Fields ID_Articulo AND ID_Compenente are related to the same table Articulos. Thats why the data is recursive. So, for the given example I have:
Rec #1 is not Tipo=1, but relates ID 1 with ID 5
Rec #2 relates ID 5 with ID 3 and Tipo=1 So, I have 1.5 (of Rec #1) * 3
Rec #3 relates ID 1 with ID 6 and Tipo=1, so i have 6
Rec #4 is from another ID
Rec #5 relates ID 6 with ID 8 but Tipo!=1 so i don't sum
Rec #6 relates ID 8 and ID 9 and Tipo=1, so I have 6 * 4.2 * 2
Final solution
This is the final code (Some field names are different):
;WITH CTE AS (
SELECT b.ID_Articulo, ID_Componente, Tipo, Cantidad,
CAST(Cantidad AS DECIMAL(6,2)) AS partialSum
FROM Arbol b inner join articulos a on a.ID_Articulo=b.ID_Componente
WHERE b.ID_Articulo = 2716
UNION ALL
SELECT t.ID_Articulo, t.ID_Componente, t.Tipo, t.Cantidad,
CAST(c.partialSum * t.Cantidad AS DECIMAL(6,2)) AS partialSum
FROM (SELECT b.ID_Articulo, ID_Componente, A.Tipo, Cantidad FROM Arbol b inner join articulos a on a.ID_Articulo=b.ID_Componente inner join Articulos a2 on a2.ID_Articulo=b.ID_Articulo where a2.Tipo<>'I') as t
INNER JOIN CTE AS c ON c.ID_Componente = t.ID_Articulo
)
SELECT SUM(partialSum)
FROM CTE
WHERE Tipo = 'I'
Thanks @giorgos-betsos for final solution
tipois 2, so according to the description, it shouldn't be included. Your example only makes your question less clear.