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Hi all I have the following Regx that can't be accepted on the JavaScript

if ($(caller).attr('value').toString().search('/(?=\D*\d\D*\d).{8,15}/g') == -1)

where 

$(caller).attr('value').toString() = "fdsddfsd45"

it returns to me -1

also I'm try to test it from pattern

  if (!pattern.test($(caller).attr('value'))) {

where

pattern = /^(?=D*dD*d).{8,15}$/

it returns to me false

$(caller).attr('value').toString() = "fdsddfsd45"

when I tried to test it through desktop application called RegExr this string "fdsddfsd45" match the expression (?=\D*\d\D*\d).{8,15} is this JavaScript bug I don't know ?

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  • If I may, what are you checking there? it looks like you're testing if the string is at least 8 characters long, and has two digits. The regex seems wrong, or at least overly complex. Can you describe what you're trying to do? One last note - you didn't say exactly what you're doing, but you may have forgotten the start and end anchors: ^...$ Commented Aug 3, 2010 at 8:51

2 Answers 2

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In JavaScript the regex should either be a string or a regex literal. In your case, this should do it:

.search(/(?=\D*\d\D*\d).{8,15}/) == -1

Note that I removed the single quotes. I've also remove the /g flag - since you are searching for any match, you don't need it.

For completeness, while it less useful, you could have written the regex as a string, but you'd have to escape all backslashes, or JavaScript will parse \d as d before it even reaches the regex. In this case, you don't need the slashes (unlike PHP, for example, which uses both):

s.search('(?=\\D*\\d\\D*\\d).{8,15}')

Example: http://jsbin.com/ubuce3

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-1 
"fdsddfsd45".search(/^(?=\D*\d\D*\d).{8,15}$/g)

will return 0, be careful the "'" character!

and 

/^(?=\D*\d\D*\d).{8,15}$/.test("fdsddfsd45")

will return true!

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