Array of pointers in Cython

Question

I have the following Cython code (the syntax is based on the post https://stackoverflow.com/a/13983740/4189299):

from libc.stdlib cimport malloc, free

def test_func():
    cdef int n = 10
    cdef char *array = <char *>malloc(n * sizeof(char*))
    for i in range(n):
        array[i] = NULL
    free(array)

It throws the compile-time error:

Error compiling Cython file:
------------------------------------------------------------
...

def test_func():
    cdef int n = 10
    cdef char *array = <char *>malloc(n * sizeof(char*))
    for i in range(n):
        array[i] = NULL
                  ^
------------------------------------------------------------

test.pyx:7:19: Cannot assign type 'void *' to 'char'

For some reason an array of char instead of char* is getting generated. Therefore, can anyone help me to obtain an array of char* in Cython?

Roman · Accepted Answer · 2015-11-10 10:24:24Z

5

I have figured it out. The correct syntax is:

cdef char **array = <char**>malloc(n * sizeof(char*))

answered Nov 10, 2015 at 10:24

Roman

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