PHP - array_unique not changing output [duplicate]

Question

I have an array $tmp:

$a = array(0 => 49, 1 => 49, 2 => 49);

after using array_unique($tmp) I'm getting this output:

Array
(
    [0] => 49
    [1] => 49
    [2] => 49
)

and I want to get

Array
(
    [0] => 49
)

What am I doing wrong? Im new in PHP

Obviously you show us not real code, or values in array are somehow different. Maybe with spaces or some hidden symbols around. Do a var_dump($tmp); — u_mulder
– u_mulder, Commented Oct 31, 2015 at 14:40

Hanky Panky · Accepted Answer · 2015-10-31 17:23:06Z

8

You don't only need to call that function you need to use the returned value as well. Do

$tmp=array_unique($tmp);

Just calling that function and not picking up the returned value does no good.

There are some functions that operate on the original variable and hence you dont need to pick up their ret val for example sort() but array_unique() is not one of them. Always refer to http://www.php.net/functionName to find out

edited Oct 31, 2015 at 17:23

answered Oct 31, 2015 at 14:43

Hanky Panky

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Funk Forty Niner · Accepted Answer · 2015-10-31 14:45:06Z

3

$input = array(49,49,49);

$result = array_unique($input);

print_r($result);

edited Oct 31, 2015 at 14:45

Funk Forty Niner

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answered Oct 31, 2015 at 14:44

Virag Shah

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1 Comment

Funk Forty Niner Over a year ago

Drop-in answer; care to "explain"? for future readers to the question.

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