convert timedelta object to time object

Question

When fetching rows from my database containing time ex 15:15:15 h/m/s. I get those in timedelta objects, i want them in time object so I later can combine them with a date object and get a datetime object.

for row in results:
    startDate = row['startDate']
    StartTime = row['startTime']
    myListStartDate.append(datestart)
    myListTimeStart.append(startTime)

When i put all the startTimes in a list and prints the list i get datetime.timedelta(0, 54900). So how do convert the timedelta to a time object so I later can compare it to other time objects.

Are you looking for something like this? timedelta.

idjaw
– idjaw

2015-10-05 23:51:07 +00:00
Commented Oct 5, 2015 at 23:51 — idjaw
– idjaw, Commented Oct 5, 2015 at 23:51

lakshayg · Accepted Answer · 2017-09-12 17:51:38Z

12

Here's how I would do it.

>>> import datetime
>>> startTime = datetime.timedelta(0, 54915)
>>> startTime = (datetime.datetime.min + startTime).time()
>>> startTime
datetime.time(15, 15, 15)

Credit goes to this post.

edited Sep 12, 2017 at 17:51

lakshayg

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answered Oct 6, 2015 at 1:00

amath

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