String splitting in Python

Question

I have hex strings split by the occurance of 'ff'. Unfortunately, f can also occur within a string, and, most importantly, at the end of a string (it cannot occur at the beginning). I need to split a string such that:

90500303040fff90500303040fff

is split into:

90500303040f
90500303040f

Whats a string-based way of going about this? (currently I'm doing it on byte level, but I'd like to learn a clean string way)

Are all the hex values of equal length?

Anand S Kumar
– Anand S Kumar

2015-09-14 15:10:24 +00:00
Commented Sep 14, 2015 at 15:10 — Anand S Kumar
– Anand S Kumar, Commented Sep 14, 2015 at 15:10
If not, you could do e.g. re.split('ff(!?f)', ...)

jonrsharpe
– jonrsharpe

2015-09-14 15:14:38 +00:00
Commented Sep 14, 2015 at 15:14 — jonrsharpe
– jonrsharpe, Commented Sep 14, 2015 at 15:14

dawg · Accepted Answer · 2015-09-14 15:27:27Z

1

>>> [e for e in re.split(r'(.*?f)?ff', '90500303040fff90500303040fff') if e]
['90500303040f', '90500303040f']

Or,

>>> re.sub(r'(f?)ff', r'\1\n', '90500303040ff90500303040fff').splitlines()
['90500303040', '90500303040f']

Or, non regex:

>>> '90500303040fff90500303040fff'.replace('fff', 'f\n').replace('ff','\n').splitlines()
['90500303040f', '90500303040f']

edited Sep 14, 2015 at 15:27

answered Sep 14, 2015 at 15:15

dawg

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