I wanna create a tuple like this:
(('0', '00:00:00'), ('1', '00:30:00'), ('2', '00:01:00') ..., ('46', '23:00:00'), ('47', '23:30:00'))
Attempts:
lines = []
a = datetime.timedelta(minutes=0)
for ii in range (48):
lines.append(a)
a = a.timedelta(minutes=30)
I tried various ways, but I don't know really what should I do?
This feels like something that can be done with datetime and timedelta objects.
For the tuple creation tuple I've used a generator expression.
>>> from datetime import datetime, timedelta
>>> dt = datetime(1970 ,1 ,1)
>>> t = timedelta(minutes=30)
>>> tuple((str(i), (dt + (i * t)).strftime("%X")) for i in range(48))
(('0', '00:00:00'), ..., ('47', '23:30:00'))
>>>
You can utilize a generator to build a list of times at 30 minute intervals.
def yield_times():
start = datetime.combine(date.today(), time(0, 0))
yield start.strftime("%H:%M:%S")
while True:
start += timedelta(minutes=30)
yield start.strftime("%H:%M:%S")
Using this generator, we can create a list of tuples. 48 in this case, is the number of iterations through the generator. This range statement will start at 0, giving us values 0 - 47.
gen = yield_times()
tuple_list = []
for ii in range(48):
tuple_list.append((ii, gen.next()))
Finally, we need to convert the list of tuples to a tuple of tuples:
tuple_times = tuple(tuple_list)
Full script:
from datetime import date, time, datetime, timedelta
def yield_times():
start = datetime.combine(date.today(), time(0, 0))
yield start.strftime("%H:%M:%S")
while True:
start += timedelta(minutes=30)
yield start.strftime("%H:%M:%S")
gen = yield_times()
tuple_list = []
for ii in range(48):
tuple_list.append((ii, gen.next()))
tuple_times = tuple(tuple_list)
Traceback (most recent call last): File "<input>", line 12, in <module> AttributeError: 'generator' object has no attribute 'next'Try use list with tuple convertion
l = []
for i in xrange(10):
l.append(('1', '00:30:00')) <--- set your data here
t =tuple(l) # convert it to tuple
