Converting string to json object using json.simple

Question

I am using org.json.simple.JSONObject. I want to convert string to Json object.

String value=request.getParameter("savepos");
JSONObject jsonObject = (JSONObject) JSONValue.parse(value);

It doesn't work. Why?

"But no success" doesn't tell us any information about the failure mode. What's the value of value? What happens with the code you've tried? — Jon Skeet
– Jon Skeet, Commented Jun 10, 2015 at 13:07
how to convert from Java object ( Sample s = new Sample()) to JSON string? — Ghost Rider
– Ghost Rider, Commented Oct 24, 2017 at 10:10

Seki · Accepted Answer · 2015-06-10 14:40:29Z

68

Try this:

JSONParser parser = new JSONParser();
JSONObject json = (JSONObject) parser.parse(stringToParse);

edited Jun 10, 2015 at 14:40

Seki

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answered Jun 10, 2015 at 13:07

Shailesh Yadav

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5 Comments

Menuka Ishan Over a year ago

Since There are Multiple JSONParser libraries, Library name would be helpful

Ghost Rider Over a year ago

how to convert from Java object ( Sample s = new Sample()) to JSON string?

Mukit09 Over a year ago

here json.simple Parser is used, I guess.

ado387 Over a year ago

@MenukaIshan You can import json-simple's parser from org.json.simple.parser.JSONParser

barrypicker Over a year ago

Why are all the examples so limited and incomplete? No import namespace included, the method seems to require a try-catch block, no example how to transfer back to string... Thanks for this idea, but it could be so much more helpful if you simply completed the thought...

Arthur Eirich · Accepted Answer · 2015-06-10 13:08:41Z

7

JSONParser parser = new JSONParser();
JSONObject json = (JSONObject) parser.parse(value);

should do the work.

answered Jun 10, 2015 at 13:08

Arthur Eirich

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Comments

Anzar Ansari · Accepted Answer · 2019-12-04 12:13:14Z

Converting String to Json Object by using org.json.simple.JSONObject

private static JSONObject createJSONObject(String jsonString){
    JSONObject  jsonObject=new JSONObject();
    JSONParser jsonParser=new  JSONParser();
    if ((jsonString != null) && !(jsonString.isEmpty())) {
        try {
            jsonObject=(JSONObject) jsonParser.parse(jsonString);
        } catch (org.json.simple.parser.ParseException e) {
            e.printStackTrace();
        }
    }
    return jsonObject;
}

Kartik Chugh · Accepted Answer · 2021-01-06 19:40:44Z

-2

In the newer com.github.cliftonlabs.json_simple the code is the following:

JsonObject obj = Jsoner.deserialize(responseString, new JsonObject());

As documented on the project's API docs

answered Jan 6, 2021 at 19:40

Kartik Chugh

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