Can't parse XML effectively using Python

Question

import urllib
import xml.etree.ElementTree as ET
def getWeather(city):

    #create google weather api url
    url = "http://www.google.com/ig/api?weather=" + urllib.quote(city)

    try:
        # open google weather api url
        f = urllib.urlopen(url)
    except:
        # if there was an error opening the url, return
        return "Error opening url"

    # read contents to a string
    s = f.read()

    tree=ET.parse(s)

    current= tree.find("current_condition/condition")
    condition_data = current.get("data")  
    weather = condition_data  
    if weather == "<?xml version=":
        return "Invalid city"

    #return the weather condition
    #return weather

def main():
    while True:
        city = raw_input("Give me a city: ")
        weather = getWeather(city)
        print(weather)

if __name__ == "__main__":
     main()

gives error , I actually wanted to find values from google weather xml site tags

File "weatxml.py", line 36, in <module> main() File "weatxml.py", line 32, in main weather = getWeather(city) File "weatxml.py", line 18, in getWeather tree=ET.parse(s) File "/usr/lib/python2.6/xml/etree/ElementTree.py", line 862, in parse tree.parse(source, parser) File "/usr/lib/python2.6/xml/etree/ElementTree.py", line 579, in parse source = open(source, "rb") IOError: [Errno 2] No such file or directory: '<?xml version="1.0"?><xml_api_reply version="1"><weather module_id="0" tab_id="0" mobile_row="0" mobile_zipped="1" row="0" section="0" ><forecast_informa... — Harshit Sharma
– Harshit Sharma, Commented Jun 17, 2010 at 18:09

Adam Crossland · Accepted Answer · 2010-06-17 18:29:07Z

3

Instead of

tree=ET.parse(s)

try

tree=ET.fromstring(s)

Also, your path to the data you want is incorrect. It should be: weather/current_conditions/condition

This should work:

import urllib
import xml.etree.ElementTree as ET
def getWeather(city):

    #create google weather api url
    url = "http://www.google.com/ig/api?weather=" + urllib.quote(city)

    try:
        # open google weather api url
        f = urllib.urlopen(url)
    except:
        # if there was an error opening the url, return
        return "Error opening url"

    # read contents to a string
    s = f.read()

    tree=ET.fromstring(s)

    current= tree.find("weather/current_conditions/condition")
    condition_data = current.get("data")  
    weather = condition_data  
    if weather == "<?xml version=":
        return "Invalid city"

    #return the weather condition
    return weather

def main():
    while True:
        city = raw_input("Give me a city: ")
        weather = getWeather(city)
        print(weather)

edited Jun 17, 2010 at 18:29

answered Jun 17, 2010 at 18:12

Adam Crossland

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3 Comments

Harshit Sharma Over a year ago

thanks that helped a lot but current=tree.find statement returns none structure of xml is as follows: <current_conditions> <condition data="Cloudy"/> <temp_f data="97"/> <temp_c data="36"/> <humidity data="Humidity: 28%"/> <icon data="/ig/images/weather/cloudy.gif"/> <wind_condition data="Wind: N at 0 mph"/>

Adam Crossland Over a year ago

@Harshit, the XML you show in your comment is not the actual XML that comes back from Google. The code that I gave you will work. Are you feeding it pretend data?

Harshit Sharma Over a year ago

ya I got that thanks It worked Thanks once again You people rock

Community · Accepted Answer · 2017-05-23 11:52:20Z

0

I'll give the same answer here I did in my comment on your previous question. In the future, kindly update the existing question instead of posting a new one.

Original

I'm sorry - I didn't mean that my code would work exactly as you desired. Your error is because s is a string and parse takes a file or file-like object. So, "tree = ET.parse(f)" may work better. I would suggest reading up on the ElementTree api so you understand what the functions I've used above do in practice. Hope that helps, and let me know if it works.

edited May 23, 2017 at 11:52

CommunityBot

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answered Jun 17, 2010 at 18:09

nearlymonolith

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3 Comments

Harshit Sharma Over a year ago

I made certain improvements in my code as below: #rest of code same s = f.read() tree=ET.fromstring(s) current= tree.find("current_conditions/condition") print current #condition_data = current.get("data") #weather = condition_data weather = current if weather == "<?xml version=": return "Invalid city" #return the weather condition return weather #code is working but returns none now below is the structure of xml file <current_conditions> <condition data="Cloudy"/> <temp_f data="97"/>

Harshit Sharma Over a year ago

it returns none although it has cloudy in it , dont know to update questions I am new here

Harshit Sharma Over a year ago

I think none is coming because tree.find is not implemented correctly following is the url google.com/ig/api?weather=london

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