6

I'm trying to execute a shell command from a java application, on the GNU/Linux platform. The problem is that the script, that calls another java application, never ends, although it runs successfully from bash. I tried to debug it:

(gdb) bt
#0  0xb773d422 in __kernel_vsyscall ()
#1  0xb7709b5d in pthread_join (threadid=3063909232, thread_return=0xbf9cb678) at pthread_join.c:89
#2  0x0804dd78 in ContinueInNewThread ()
#3  0x080497f6 in main ()

I tried with: ProcessBuilder(); and Runtime.getRuntime().exec(cmd);

Looks like it waits for something to finish. Any ideas?

Thanks, Laurențiu

3
  • Are you saying that the second Java program is expected to finish quickly but the shell invoking it still hangs around? Have you confirmed the second Java process is actually finished (cheking process listing)? Commented Jun 17, 2010 at 14:21
  • Looks like the Process class from Java is terrible slow. I started the java application from the shell with production (non-verbose) parameters and it finished after a while. Commented Jun 17, 2010 at 14:26
  • Yes I checked the processes list and the process is still there. I think that dsmith answered my question. Commented Jun 18, 2010 at 15:50

1 Answer 1

15

Are you processing the standard input and standard output? From the javadocs:

Because some native platforms only provide limited buffer size for standard input and output streams, failure to promptly write the input stream or read the output stream of the subprocess may cause the subprocess to block, and even deadlock.

Process cmdProc = Runtime.getRuntime().exec(command);


BufferedReader stdoutReader = new BufferedReader(
         new InputStreamReader(cmdProc.getInputStream()));
String line;
while ((line = stdoutReader.readLine()) != null) {
   // process procs standard output here
}

BufferedReader stderrReader = new BufferedReader(
         new InputStreamReader(cmdProc.getErrorStream()));
while ((line = stderrReader.readLine()) != null) {
   // process procs standard error here
}

int retValue = cmdProc.exitValue();
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1 Comment

Thanks, this solved my problem ;-). Next time I should read the documentation more carefully.

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