$array=@("blue","green","black")
[string]$input=Read-host "Input:"
$array[$input]
If I enter the number 1 into the input this gives no output. When I
Write-host $input
I get
System.Collections.ArrayList+ArrayListEnumeratorSimple
What I'm looking to do next is:
$inputlist=@("0")
$inputlist += $array[$input]
But I seem to end up with an array where each element is a single letter. I would like them to be one string in $inputlist[1].
$Input is an automatic variable and shouldn't be used in the way you do. Give your variable a different name and the problem will disappear:
PS C:\> $array = @('blue', 'green', 'black')
PS C:\> $val = Read-host 'Input'
Input: 2
PS C:\> $val
2
PS C:\> $val.GetType().FullName
System.String
PS C:\> $array[$val]
greenSplitting the string into an array of single characters can be handled by casting the string to a character array and then to a string array:
PS C:\> [string[]][char[]]$array[$val]
g
r
e
e
nYou'd still be able to append the characters to an array if you cast the string just to char[] (without casting it to string[] afterwards), but then you'd have an array with mixed types:
PS C:\> $inputList = @('0')
PS C:\> $inputList += [char[]]$array[$val]
PS C:\> $inputList
0
g
r
e
e
n
PS C:\> $inputList[0].GetType().FullName
System.String
PS C:\> $inputList[1].GetType().FullName
System.CharIf you want the entire string as the second element of the array, your existing code should already do that:
PS C:\> $inputList = @('0')
PS C:\> $inputList += $array[$val]
PS C:\> $inputList
0
green
0, greenor0, g, r, e, e, n?$inputlist = @("0"); $inputlist += $array[$val]will already do the former.