I have a method being posted to via AJAX with the following header:
public JsonResult GetDocuments(string searchTerm, SortRequest sort)
The SortRequest object is defined as follows:
[DataContract]
public class SortRequest
{
[DataMember(Name = "field")]
public string Field { get; set; }
[DataMember(Name = "dir")]
public string Direction { get; set; }
}
Because of legacy code, the JSON object has the property name "dir" which doesn't directly match the C# property name. We want to use Json.NET as the model binder for JSON requests because it is able to handle this, but the problem is that the JSON coming into the model binder looks like a single object with two top level properties, "searchTerm" and "sort". The deserialization process then tries to map that entire JSON string into each method parameter which obviously fails.
I have tried looking through the now open source .NET MVC code and have not yet been able to determine how the DefaultModelBinder class handles this gracefully. The only option I can see so far is to convert every JSON action to take in a single request parameter but this doesn't seem like a good solution as the DefaultModelBinder doesn't require this.
Edit for clarification:
The JSON request string looks something like this:
{
"searchTerm": "test",
"sort": {
"field": "name",
"dir": "asc"
}
}
We are overriding the DefaultModelBinder and only using Json.NET when the request is of type application/json. Here is the relevant code:
var request = controllerContext.HttpContext.Request;
request.InputStream.Seek(0, SeekOrigin.Begin);
using (var reader = new StreamReader(request.InputStream))
{
var jsonString = reader.ReadToEnd();
result = JsonConvert.DeserializeObject(jsonString, bindingContext.ModelType);
}
The bindingContext.ModelType is going to be set to String and SortRequest for each parameter in the method, but since the above is a single JSON object, it doesn't map to either of those types and thus inside the method itself, everything is set to default values.
[JsonProperty()], and use it in yourModel, for everyproperty.