Convert a string into an hexadecimal

Question

I have a string file, but the strings in it represent hexadecimal values. For example, I have this kind of string in my file:

1091    A3B7    56FF    ...

And I don't want to use them as string, but as hexadecimal values; and then convert the hexadecimal into an int.

For example:

1091(in string)---> 1091(in hexa)---> 4241 # The int value of 1091 in hexa

So I looked on the Internet. I tried a lot of different methods such as:

But nothing fit exactly with what I need, or simply does not work.

This is a part of my code:

t = False
i = 0
while t != True and h != True or i <=100: # My way to look each string of my file
    file = row[1]
    read_byte = file[i]

    if read_byte == 'V': #V is the letter in my file which says that it s the data that I want then there is 2 kinds of channel 01 and 02 that interest me

        i=i+1
        a=i+2
        read_bytechannel = file[i:a]  #read 2 strings because the channel can be '01' or '02'

        if read_bytechannel == '01':
            print(read_bytechannel)
            i=i+1
            a=i+4
            read_bytetemp = file[i:a] # Reading 4 strings because the value is the int value of the two hexa.
            realintvalue= # (?????????convert the read_bytetemp string value into an hexa value, then into an int from the hexa)

            tempfinal = realintvalue/100 # I have to divide by 100 the int value to get the real temperature
            t = True # This condition just tell me that I already know the temporary

    i = i+1

And this is the kind of file I want to read:

@
I01010100B00725030178
V01109103
I02020100B00725030148
V0215AA5C
$
@

Your input is not hexadecimal and it does not look like the 1091 A3B7 56FF you describe at the beginning. What is your real input? — user1907906
– user1907906, Commented Apr 7, 2015 at 15:11
My initial input are byte from a serial usb, that I put into an sql database, then now I am analysing the datum, so I have to read from the database. But what I showed you at the end of my question, was exactly what I get if I look the file created by the serial read of my script. — Max Taylor
– Max Taylor, Commented Apr 7, 2015 at 15:21
Please provide a sample of your real input and describe the structure. — user1907906
– user1907906, Commented Apr 7, 2015 at 15:23

C.B. · Accepted Answer · 2015-04-07 15:06:32Z

1

>>> int('1091', 16)
4241

The second parameter to int is the base which to interpret the first parameter.

answered Apr 7, 2015 at 15:06

C.B.

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Comments

Peter Mortensen · Accepted Answer · 2018-07-03 01:55:21Z

1

You can try something like this, int with base 16:

>>> my_string = "1091 A3B7 56FF"
>>> map(lambda x:int(x,16), my_string.split())
[4241, 41911, 22271]

Or you can have both:

>>> map(lambda x:[x,int(x,16)], my_string.split())
[['1091', 4241], ['A3B7', 41911], ['56FF', 22271]]

If you are not comfortable with lambda and map, you can use list comprehension:

>>> [[x,int(x,16)] for x in my_string.split()]
[['1091', 4241], ['A3B7', 41911], ['56FF', 22271]]

edited Jul 3, 2018 at 1:55

Peter Mortensen

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answered Apr 7, 2015 at 15:13

Hackaholic

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2 Comments

Max Taylor Over a year ago

Thank you, but what if my strong is only 1091? because I tried you method, and it gives me: <map object at 0x1006b8b70> this as an answer and I would like 4241. Thank you again

Hackaholic Over a year ago

@MaxTaylor if you using python3, apply list, like this list(map(lambda x:int(x,16), my_string.split()))

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