I want to make and array that contains arrays, some are of double's, some are of int's.
This does not work:
var arrayZero = [1,2,3]
var arrayOne = [4.0,5.0,6.0]
var arrayofArrayZeroandOne: [[AnyObject]] = arrayZero.append(arrayOne)
How can I append arrays to an array so that I can get 5.0 if I write arrayofArrayZeroandOne[1][1] ?
I would take advantage of Swift's type safety. Going the Any route could introduce bugs if you're not careful adding and retrieving from the array.
var numbers = Array<Array<NSNumber>>() // A bit clearer IMO
var numbers = [[NSNumber]]() // Another way to declare
numbers.append(arrayZero)
numbers.append(arrayOne)
Then when you do something like
let five = numbers[1][1] // will be 5.0
You know it will be of type NSNumber. Further Swift won't let you put anything else into the array unless it's an NSNumber
Without appends solution
var numbers = Array<Array<NSNumber>>() [
[1,2,3,4],
[1.0,2.0,3.0,4.0]
]
You're looking for [[Any]] (and note that append mutates in place):
let arrayZero = [1, 2, 3]
let arrayOne = [4.0, 5.0, 6.0]
let arrayofArrayZeroAndOne: [[Any]] = [arrayZero, arrayOne]
let a = arrayofArrayZeroAndOne[0][0] // of type Any
You do not need an append, you can construct the array directly:
var arrayZero = [1, 2, 3]
var arrayOne = [4.0, 5.0, 6.0]
var arrayofArrayZeroandOne: [[AnyObject]] = [arrayZero, arrayOne]
println(arrayofArrayZeroandOne[1][1]) // Prints 5
