split string into array with multiple delimiters shell

Question

I have a text file having contents in format...

File=/opt/mgtservices/probes/logs is_SS_File=no is_Log=yes Output_File=probes_logs

This can have around 1k records. I am reading line by line from a file.

while read -r line
do
  if [ $SS_SERVER -eq 0 ]
  then
    arr=$(echo "$line" | tr ' =' "\n")
    echo $arr[1]
    #do something
  elif [[ $SS_SERVER -eq 1 && "$line" =~ "is_SS_File=\"no\"" ]]
  then
    #do something else
  fi
done < "$filename"

I am expecting that arr should be an array, so that I can get output as:

arr[1]=File
arr[2]=/opt/mgtservices/probes/logs
arr[3]=is_SS_File
and so on...

Which I am not getting here. arr[1] is giving me complete line without "=" I want to use 2 delimiters "space" and "=".

What is the meaning and significance of SS_SERVER and where is it being set? — tripleee
– tripleee, Commented Mar 11, 2015 at 9:01
@tripleee...SS_SERVER is a flag which I can get from calling function. It can be 0 or 1. — pankaj_ar
– pankaj_ar, Commented Mar 11, 2015 at 9:04
@triplee yes, you can say like that, basically my intention is to split string with multiple delimiters into array — pankaj_ar
– pankaj_ar, Commented Mar 11, 2015 at 9:15

tripleee · Accepted Answer · 2015-03-11 09:16:35Z

1

Depending on what you are trying to accomplish try this:

tr ' =' '\n ' <"$file" |
while read keyword value; do
    : you get one keyword and its value at a time now
done

or maybe

while IFS=' =' read -a arr; do
    : arr[0] is first keyword
    : arr[1] is its value
    : arr[2] is second keyword
    : etc
done <"$file"

answered Mar 11, 2015 at 9:16

tripleee

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