Parse unicode JSON string

Question

I've some difficulties to parse a unicode JSON string.

sample:

js = "{'to': 1234, 'message': u'sample message', 'user': 65773722, 'msgId': 28198}"

I want to iterate the JSON object to retrieve the values.

I've already tried, json.dumps, json.loads and js.decode('unicode-escape'), but I keep getting error messages.

Please help..I'm stuck !

Many thanks !

That is not a valid json string. The string should be enclosed using " and not ', also the u'' is not valid. Use something like jsonlint.com to validate. If you use Chrome I would recommend chrome.google.com/webstore/detail/json-formatter/… to validate and view json well formatted. — edepe
– edepe, Commented Mar 7, 2015 at 18:14
js is not a unicode string, but a bytestring that happens to contain a unicode literal. It is not clear whether you are trying to construct a valid json string, or whether you are trying to parse a string that someone else gave you (that only pretends to be valid json). — Terry Jan Reedy
– Terry Jan Reedy, Commented Mar 7, 2015 at 21:22

Ignacio Vazquez-Abrams · Accepted Answer · 2015-03-07 16:02:50Z

3

Unfortunately someone goofed, and that's not JSON.

>>> ast.literal_eval(js)
{'to': 1234, 'message': u'sample message', 'user': 65773722, 'msgId': 28198}

answered Mar 7, 2015 at 16:02

Ignacio Vazquez-Abrams

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6 Comments

John Doe Over a year ago

@Ignaciao; I do not understand what you mean. Please explain !

Ignacio Vazquez-Abrams Over a year ago

String not JSON. JSON functions not work. Find other way to parse.

John Doe Over a year ago

Treat it as a dictionary maybe ?

Ignacio Vazquez-Abrams Over a year ago

It's a string. It needs to be parsed before you can access it.

Darbio Over a year ago

It is JSON, the u at the beginning of the string shows that it's encoded in unicode see here

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VelikiiNehochuha · Accepted Answer · 2015-03-07 19:12:23Z

1

it is not valid json

s = "{'to': 1234, 'message': u'sample message', 'user': 65773722, 'msgId': 28198}"
valid = s.replace("u'", "'")
supervalid = v.replace("'", '"')
json.loads(super_valid)

answered Mar 7, 2015 at 19:12

VelikiiNehochuha

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2 Comments

John Doe Over a year ago

I'am convinced (except for the errors in the variables) ;-))

VelikiiNehochuha Over a year ago

Yes =), valid = s.replace("u'", "'"); supervalid = valid.replace("'", '"'); json.loads(supervalid)

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