What is the difference between [].slice vs Array.prototype.slice?
While searching, I found Array.prototype.slice to be faster than [].slice at jsperf.com/array-prototype-slice-vs-slice.
Why Array.prototype.slice is faster than [].slice?
I have checked [].slice or Array.prototype.slice. A more vivid description will be helpful.
Thanks
Why Array.prototype.slice is faster than [].slice?
[] is an instance of Array, so the additional overhead is most likely the time it takes to instantiate the object.
.slice() is an Array prototype method. It is defined on the Array prototype object, Array.prototype, which means that Array.prototype.slice is the direct way to reference it.
Array instances, like [], inherit from the Array prototype, so [].slice resolves to Array.prototype.slice.
If you need to use this method repeatedly, a good approach is to put its reference into a variable in your outermost scope:
var slice = Array.prototype.slice;
and then use this variable via .call() and .apply() calls, e.g.
slice.call( someObj )
