How does OkHttp get Json string?

Question

Solution: It was a mistake on my side.

The right way is response.body().string() other than response.body.toString()

Im using Jetty servlet, the URL ishttp://172.16.10.126:8789/test/path/jsonpage, every time request this URL it will return

{"employees":[
    {"firstName":"John", "lastName":"Doe"}, 
    {"firstName":"Anna", "lastName":"Smith"},
    {"firstName":"Peter", "lastName":"Jones"}
]}

It shows up when type the url into a browser, unfortunately it shows kind of memory address other than the json string when I request with Okhttp.

TestActivity﹕ com.squareup.okhttp.internal.http.RealResponseBody@537a7f84

The Okhttp code Im using:

OkHttpClient client = new OkHttpClient();

String run(String url) throws IOException {
  Request request = new Request.Builder()
      .url(url)
      .build();

  Response response = client.newCall(request).execute();
  return response.body().string();
}

Can anyone helpe?

It constructs String object from the char bytes and charset. — Nikola Despotoski
– Nikola Despotoski, Commented Jan 30, 2015 at 21:07
@NikolaDespotoski thanks! It was my own mistake. I replaced response.body().string() to response.body().toString()... — Haifeng Zhang
– Haifeng Zhang, Commented Feb 2, 2015 at 16:37
@haifzhan Thanks for clarifying the use of response.body().string() instead of response.body().toString() — user3144836
– user3144836, Commented Feb 16, 2016 at 4:07

gfullam · Accepted Answer · 2015-04-16 17:24:01Z

142

try {
    OkHttpClient client = new OkHttpClient();
    Request request = new Request.Builder()
        .url(urls[0])
        .build();
    Response responses = null;

    try {
        responses = client.newCall(request).execute();
    } catch (IOException e) {
        e.printStackTrace();
    }
    String jsonData = responses.body().string();
    JSONObject Jobject = new JSONObject(jsonData);
    JSONArray Jarray = Jobject.getJSONArray("employees");

    for (int i = 0; i < Jarray.length(); i++) {
        JSONObject object     = Jarray.getJSONObject(i);
    }
}

Example add to your columns:

JCol employees  = new employees();
colums.Setid(object.getInt("firstName"));
columnlist.add(lastName);

edited Apr 16, 2015 at 17:24

gfullam

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answered Apr 16, 2015 at 16:33

Newbies

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6 Comments

Gokul NC Over a year ago

I'm now getting the exception:

org.json.JSONException: Value okhttp3.internal.http.RealResponseBody@aeb56f3 of type java.lang.String cannot be converted to JSONObject

Zapnologica Over a year ago

very easy mistake is to confuse .string() with '.toString()'

Diego Alves Over a year ago

You should specify where you get the objects from, like the JSONObject. please, Include the imports too.

RoCkDevstack Over a year ago

I'm trying to do simple request using Okhttp (3.x.x), is this the basic for request?

Chakib Temal Over a year ago

responses.body().string() can be called just one time <br/> use this code directlty : //String jsonData = responses.body().string(); JSONObject Jobject = new JSONObject(responses.body().string());

|

Paolo Forgia · Accepted Answer · 2020-07-01 08:43:49Z

28

I am also faced the same issue

use this code:

// notice string() call
String resStr = response.body().string();    
JSONObject json = new JSONObject(resStr);

it definitely works

edited Jul 1, 2020 at 8:43

Paolo Forgia

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answered Dec 26, 2015 at 11:49

Venkat Veeravalli

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5 Comments

Leo DroidCoder Over a year ago

Thank's a lot! Interesting that there is no info about string() method in documentation. But it actually works

Anthony Over a year ago

Thanks so much for this answer. This helped me out a lot! Strange how I could not find this anywhere else on the internet!

Ronak Gadhia Over a year ago

Thank u so much.It's strange about string() but it works great!

Paixols Over a year ago

For OKHttp3 GraphQL responses that include the data and error object, this also applies.

portfoliobuilder Over a year ago

Isn't adding toString() redundant? You should only require response.body().string(). That returns back String.

Sᴀᴍ Onᴇᴌᴀ · Accepted Answer · 2017-07-21 19:05:30Z

24

As I observed in my code. If once the value is fetched of body from Response, its become blank.

String str = response.body().string();  // {response:[]}

String str1  = response.body().string();  // BLANK

So I believe after fetching once the value from body, it become empty.

Suggestion : Store it in String, that can be used many time.

edited Jul 21, 2017 at 19:05

Sᴀᴍ Onᴇᴌᴀ

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answered Jul 17, 2017 at 12:08

Kuldip Sharma

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2 Comments

Saad Ismail Over a year ago

Thank you so much. Been trying to figure out this for a while and none of the above answers actually helped because I was first logging whole body and then trying to get the string and this was actually the issue.

Abdullah Over a year ago

that is correct. What a silly situation

Phillip Kigenyi · Accepted Answer · 2015-08-01 14:04:15Z

I hope you managed to obtain the json data from the json string.

Well I think this will be of help

try {
OkHttpClient client = new OkHttpClient();
Request request = new Request.Builder()
    .url(urls[0])
    .build();
Response responses = null;

try {
    responses = client.newCall(request).execute();
} catch (IOException e) {
    e.printStackTrace();
}   

String jsonData = responses.body().string();

JSONObject Jobject = new JSONObject(jsonData);
JSONArray Jarray = Jobject.getJSONArray("employees");

//define the strings that will temporary store the data
String fname,lname;

//get the length of the json array
int limit = Jarray.length()

//datastore array of size limit
String dataStore[] = new String[limit];

for (int i = 0; i < limit; i++) {
    JSONObject object     = Jarray.getJSONObject(i);

    fname = object.getString("firstName");
    lname = object.getString("lastName");

    Log.d("JSON DATA", fname + " ## " + lname);

    //store the data into the array
    dataStore[i] = fname + " ## " + lname;
}

//prove that the data was stored in the array      
 for (String content ; dataStore ) {
        Log.d("ARRAY CONTENT", content);
    }

Remember to use AsyncTask or SyncAdapter(IntentService), to prevent getting a NetworkOnMainThreadException

Also import the okhttp library in your build.gradle

compile 'com.squareup.okhttp:okhttp:2.4.0'

If you noticed, once you download a file, there will be a blinking white down arrow at your statusbar. Indicating you download something. That is handle by DownloadManager

Deven · Accepted Answer · 2020-02-14 10:20:19Z

Below code is for getting data from online server using GET method and okHTTP library for android kotlin...

Log.e("Main",response.body!!.string())

in above line !! is the thing using which you can get the json from response body

val client = OkHttpClient()
            val request: Request = Request.Builder()
                .get()
                .url("http://172.16.10.126:8789/test/path/jsonpage")
                .addHeader("", "")
                .addHeader("", "")
                .build()
            client.newCall(request).enqueue(object : Callback {
                override fun onFailure(call: Call, e: IOException) {
                    // Handle this
                    Log.e("Main","Try again latter!!!")
                }

                override fun onResponse(call: Call, response: Response) {
                    // Handle this
                    Log.e("Main",response.body!!.string())
                }
            })

shoolpani dubey · Accepted Answer · 2022-03-22 09:59:36Z

1

I would like to add one more observation. You can call .string() method only once. If you try to call it twice, it will give you illegal state exception.

answered Mar 22, 2022 at 9:59

shoolpani dubey

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1 Comment

Community Over a year ago

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