I'm trying to figure out the equivalent of:
foo = []
foo << "bar"
foo << "baz"
I don't want to have to come up with an incrementing index. Is there an easy way to do this?
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12The entire documentation is available at lua.org/manual/5.2rsethc– rsethc2014-12-11 23:14:29 +00:00Commented Dec 11, 2014 at 23:14
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7oh that's really helpful. google kept pointing me towards lua.org/pil/2.5.html which is basically useless.drewish– drewish2014-12-11 23:15:36 +00:00Commented Dec 11, 2014 at 23:15
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3 Answers
You are looking for the insert function, found in the table section of the main library.
foo = {}
table.insert(foo, "bar")
table.insert(foo, "baz")
2 Comments
AStopher
@rsethc Two 'duplicate' answers were bound to be posted at the same moment sometime in Stack Overflow's history (and I bet we won't be the last to, either). To be fair I did add some information about memory/time savings.
Wolf
I think it would be helpful to point out that the second parameter, which specifies the insert position, is optional. The function itself does a good job, but the naming is unfortunately not entirely obvious.
foo = {}
foo[#foo+1]="bar"
foo[#foo+1]="baz"
This works because the # operator computes the length of the list. The empty list has length 0, etc.
If you're using Lua 5.3+, then you can do almost exactly what you wanted:
foo = {}
setmetatable(foo, { __shl = function (t,v) t[#t+1]=v end })
_= foo << "bar"
_= foo << "baz"
Expressions are not statements in Lua and they need to be used somehow.
I'd personally make use of the table.insert function:
table.insert(a,"b");
This saves you from having to iterate over the whole table therefore saving valuable resources such as memory and time.
1 Comment
Kangaroos In Antarctica
So a_table:insert("b")