Using enum in c++

Question

How to define LogLevel variable l?

Currently I have error:

 Error  3   error C2228: left of '.LogLevelDebug' must have class/struct/union

Code:

typedef enum LogLevel
{
    LogLevelDebug = 0,
    LogLevelError = 1,
    LogLevelInfo = 2,
    LogLevelTrace = 3,
} LogLevel;



int main ()
{
logLevel l = LogLevel.LogLevelDebug;
}

I think "logLevel l" needs to be "LogLevel l"? Also, this question seems to be more about enumerations than unions. — Serge
– Serge, Commented Dec 2, 2014 at 17:31
Remove the typedef. It's not needed in C++, confuses people and makes things difficult, as you have found out. — Thomas Matthews
– Thomas Matthews, Commented Dec 2, 2014 at 18:09

Dmitry Ledentsov · Accepted Answer · 2014-12-02 17:33:40Z

3

In c++11 it would be:

enum class LogLevel
{
 LogLevelDebug = 0,
 LogLevelError = 1,
 LogLevelInfo = 2,
 LogLevelTrace = 3,
};



int main ()
{
 LogLevel l = LogLevel::LogLevelDebug;
}

in a previous C++ standard:

enum LogLevel
{
    LogLevelDebug = 0,
    LogLevelError = 1,
    LogLevelInfo = 2,
    LogLevelTrace = 3,
};

int main ()
{
    LogLevel l = LogLevelDebug;
}

answered Dec 2, 2014 at 17:33

Dmitry Ledentsov

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2 Comments

Serge Over a year ago

Oh my goodness I've been in C# so long I'd forgotten about ::

Yakk - Adam Nevraumont Over a year ago

Last I read, even in C++03 enums can be read as a legal scope on their names (ie, LogLevel::LogLevelDebug may be legal in C++03). Something about the enum being part of a more general class of thing... I guess it matters more if your compiler and potential future compilers support it.

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