I want to pass php variable value as a action to html form. I am trying as follows, but it is not working.
<?php
$url='test.php';
?>
<html>
<body>
<form name="upload" action="<?=$url?>" method="post" >
<input type="submit" value="submit">
</form>
</body>
</html>
All this code are in one php file.
Have you tried <?php echo $url ?>
If it works, then short_open_tag in the php.ini is turned off. That means you will need to either turn it on or use the long open tag <?php throughout your code.
Sounds like you need to enable short_open_tag if your example doesn't work.
<?php
ini_set('short_open_tag', 'on');
$url='test.php';
?>
<html>
<body>
<form name="upload" action="<?=$url?>" method="post" >
<input type="submit" value="submit">
</form>
</body>
</html>
Alternately, write it like this:
<?php
$url='test.php';
?>
<html>
<body>
<form name="upload" action="<?php echo $url ?>" method="post" >
<input type="submit" value="submit">
</form>
</body>
</html>
Try this
<form name="upload" action="<? echo $url ?>" method="post" >
<form name="upload" action"<?=$url;?>" method="post">, without the single quotes wrapping the php snippet.
Remove your single quotes:
<form name="upload" action="<?=$url?>" method="post">
