How to convert hex string to integer in Python?

Question

How to convert

x = "0x000000001" # hex number string

to

y = "1"

Answer 1

You can do:

y = int("0x000000001", 16)

in your case:

y = int(x, 16)

Looks like you want the int converted to string:

y = str(int(x, 16))

Answer 2

Use int() and provide the base which your number is in (in your case 16).
Then apply str() to convert it back to a string:

y = str(int(x, 16))

Note: If you omit the base then the default base 10 is used which would result in a ValueError in your case.

Answer 3

>>> int("0x000000001", 16)
1

Answer 4

Python 2.7 have a problem to convert hex from read binary file

Python 3 not have this problem

f=open(file_name,'rb')
raw = f.read()

print int(raw[6])    #error invalid literal for int with base 10:
print ord(raw[6])    #Work

Answer 5

you can do:

y = int(x, 0)  # '0' ;python intepret x according to string 'x'.

In the offical documentation, it is explained as "If base is zero, the proper radix is determined based on the contents of the string;"