JSON string assignment not working

Question

What is wrong with my code below? I am passing to this function a JSON string but the assignment ends up blank. I can see the string in FireBug in the function parameter so I know it arrives at the function, but it does not make it past the assignment (as in the assignment is "undefined"). I want to pull from the string the wty_upgrade array. I am using some of the code I received help with in this question. Thanks

JSON string (as I see it in FireBug:

{"wty_upgrade":[
    {"wty":"Upgrade from 3 to 5 years", "mth":24, "pig":3000}, 
    {"wty":"Upgrade from 3 to 10 years", "mth":84, "pig":8000}
]}

Function Call:

LoadWtyUpgPlans('3', JSON)

function LoadWtyUpgPlans(StdWty, UpgWty) {
    var WtyRow = '';
    var WtyUpgrades = UpgWty.wty_upgrade;    <--- here the assignment is blank/undefined
    STUFF HERE...
};

Is the first part meant to be JavaScript code, or....? If you're just quoting your JSON, remove the JSON = " at the beginning and the " at the end (e.g., as in the question you linked). — T.J. Crowder
– T.J. Crowder, Commented Sep 20, 2014 at 7:31
Hi @T.J. Crowder, you are correct it is not code. I get the value from a MySQL tabke field. Is the syntax of the JSON incorrect somehow? — TheRealPapa
– TheRealPapa, Commented Sep 20, 2014 at 7:38
@TheRealPapa can you show how you output the JSON to the page after you've retrieved it from the database? — cmbuckley
– cmbuckley, Commented Sep 20, 2014 at 7:42
Hi @T.J. Crowder, apologies again, I should have removed the ". I even checked the validity of JSON syntax here http://jsonlint.com/ and it is OK (without the outside "). — TheRealPapa
– TheRealPapa, Commented Sep 20, 2014 at 7:43
if I alert(JSON) it looks exactly as above. If I alert(JSON.wty_upgrade) it shows up undefined — TheRealPapa
– TheRealPapa, Commented Sep 20, 2014 at 7:45

Kamal · Accepted Answer · 2014-09-20 07:47:16Z

0

you can use as a this example may be useful fir you,
var jsn = '{"wty_upgrade":[
{"wty":"Upgrade from 3 to 5 years", "mth":24, "pig":3000}, 
{"wty":"Upgrade from 3 to 10 years", "mth":84, "pig":8000}]}';


 //OR you can parse then use
jsonres = JSON.parse(jsn);

answered Sep 20, 2014 at 7:47

Kamal

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1 Comment

TheRealPapa Over a year ago

It seems to be working after JSON.parse now. I do not understand why it needs to, but it works. Thank you!

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