Put array elements with specific value to end of array

Question

I have a multidimensional array like that:

$array = array(
    1 => array(
         "name" => 'Jon',
         "year" => '2012'
    ),
    2 => array(
         "name" => 'Jack',
         "year" => '1900'
    ),
    3 => array(
         "name" => 'Lisa',
         "year" => '1900'
    ),
    4 => array(
         "name" => 'Ygritte',
         "year" => '1929'
    ),
);

All the items that have a year of '1900' should be put to the end of the array. What is a lightweight solution?

Desired result:

$array = array(
    1 => array(
         "name" => 'Jon',
         "year" => '2012'
    ),
    2 => array(
         "name" => 'Ygritte',
         "year" => '1929'
    ),
    3 => array(
         "name" => 'Jack',
         "year" => '1900'
    ),
    4 => array(
         "name" => 'Lisa',
         "year" => '1900'
    ),
);

"without changing the order of the other items" shouldn't the order in the desired output and input be the same then? Which rules do the swaps follow? Also what have you tried, a simple loop should already be able to do the trick — kero
– kero, Commented Jul 24, 2014 at 9:51
It is pretty trivial, so it is time to write a clever foreach loop. Hint: you'll need two temporary arrays with all chance. — moonwave99
– moonwave99, Commented Jul 24, 2014 at 9:51

Marcin Nabiałek · Accepted Answer · 2014-07-24 10:14:47Z

I assume you don't care about your indexes because you rearrange them. First thing, you should probably start indexes in your array from 0 and not for 1.

You can use the following code:

$array = array(
    1 => array(
         "name" => 'Jon',
         "year" => '2012'
    ),
    2 => array(
         "name" => 'Jack',
         "year" => '1900'
    ),
    3 => array(
         "name" => 'Lisa',
         "year" => '1900'
    ),
    4 => array(
         "name" => 'Ygritte',
         "year" => '1929'
    ),
);


$array = array_values($array);


for ($i=0, $c = count($array); $i<$c; ++$i) {
    if ($array[$i]['year'] == '1900') {
        $array[] = $array[$i];
        unset($array[$i]);
    }

}

$array = array_values($array);



foreach ($array as $k => $v) {
    echo $k.' '.$v['name'].' '.$v['year']."<br />";

}

Result for this is:

0 Jon 2012
1 Ygritte 1929
2 Jack 1900
3 Lisa 1900

Of course if you want, you can change your keys adding 1 to each one (starting from the last element) so you have the same output as in question but I assume this one is enough for you.

MixedVeg · Accepted Answer · 2014-07-24 09:58:08Z

0

The simplest approach could be something like this: Find the element that has year 1900 (iterating the loop) then,

For example working for index 3

$tmp = $myArray['3'];
unset($myArray['3'];
$myArray['3'] = $tmp;

$tmp is a temporary variable inside the loop.

answered Jul 24, 2014 at 9:58

MixedVeg

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Comments

cornelb · Accepted Answer · 2014-07-24 10:06:20Z

0

Try using SplHeap

class MyQueue extends SplHeap
{
    public function compare($item1, $item2)
    {
        if ($item1['year'] === $item2['year']) return 0;
        return ($item1['year'] == 1900) ? -1 : 0;
    }
}

$queue = new MyQueue();
foreach ($array as $item) {
    $queue->insert($item);
}

$queue->top();
$array = array();
while($queue->valid()){
    $array[] = $queue->current();
    $queue->next();
}

print_r($array);

answered Jul 24, 2014 at 10:06

cornelb

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Comments

Teerath Kumar · Accepted Answer · 2014-07-24 10:09:20Z

0

Hope this following code will help you:

function aasort (&$array, $key) {
$sorter=array();
$ret=array();
reset($array);
foreach ($array as $ii => $va) {
    $sorter[$ii]=$va[$key];
}
rsort($sorter);
foreach ($sorter as $ii => $va) {
    $ret[$ii]=$array[$ii];
}
$array=$ret;
}

aasort($array,"year");
print_r($array);

edited Jul 24, 2014 at 10:09

answered Jul 24, 2014 at 10:04

Teerath Kumar

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