i am trying to execute unix command in php script like this.
<?php
echo shell_exec('head -n 1 log_list_23072014|awk -F ',' '{print $2}'');
?>
This is the file , trying to get the first column of the first row.
NODE,CGR,TERMID,VMGW,ET
but the error message i am getting
Parse error: syntax error, unexpected 'shell_exec' (T_STRING), expecting ',' or ';'.
cant able to find please help.
The string you've used is not valid, you have to escape single quotes inside your string:
<?php echo shell_exec('head -n 1 log_list_23072014|awk -F \',\' \'{print $2}\'');
You can also use exec()
awk can do the equivalent of head -n1 by itself: ' awk -F, \'NR==1{print $2;exit}\' 'There was an extra ' within your command. Using your command in a variable can help with identifying errors, and when using the standard exec it's required.
$cmd = 'head -n 1 log_list_23072014 | awk -F , \'{print $2}\'';
echo shell_exec($cmd);
changing it to the format above should work.
shell_exec()expects 1 parameter, you're parsing 2.shell_exec(FIRSTITEM , SECOND ITEM);and the function can only do thisshell_exec(FIRSTITEM);