I have always heard that C++ was way more efficient than Java (and that is why most games are developed in C++).
I wrote a small algorithm to solve the "Eight queens puzzle" in both Java and C++, using the exact same algorithm, and then started to raise the number or squares. When reaching checkboards of 20*20 or even 22*22, it appears Java is much more effective (3 seconds vs 66 seconds for C++).
I have no idea why, but I am pretty beginning with C++, so it is possible I made some huge performance mistakes, so I will gladly accept any information that would help me understand what is happening.
Below is the code I use in Java:
import java.awt.Point;
import java.util.ArrayList;
import java.util.List;
public class HuitDames {
/**
* La liste des coordnnées des dames.
*/
private static List<Point> positions = new ArrayList<>();
/**
* Largeur de la grille.
*/
private static final int LARGEUR_GRILLE = 22;
/**
* @param args the command line arguments
*/
public static void main(String[] args) {
int i = 1;
placerDame(i);
for (Point point : positions) {
System.out.println("(" + point.x + "; " + point.y + ")");
}
}
/**
* Place une dame et return true si la position est bonne.
* @param i le numéro de la dame.
* @return si la position est bonne.
*/
private static boolean placerDame(int i) {
boolean bonnePosition = false;
for (int j = 1; j <= LARGEUR_GRILLE && bonnePosition == false; j++) {
Point emplacement = new Point(i, j);
positions.add(emplacement);
if (verifierPrise(emplacement) && (i == LARGEUR_GRILLE || placerDame(i + 1))) {
bonnePosition = true;
}
else {
positions.remove(i - 1);
}
}
return bonnePosition;
}
/**
* Vérifie que la nouvelle position n'est pas en prise avec une position déjà présente.
* @param position la position de la nouvelle dame.
* @return Si la position convient par rapport aux positions des autres dames.
*/
private static boolean verifierPrise(Point position) {
boolean nonPrise = true;
for (Point point : positions) {
if (!point.equals(position)) {
// Cas où sur la même colonne.
if (position.y == point.y) {
nonPrise = false;
}
// Cas où sur même diagonale.
if (Math.abs(position.y - point.y) == Math.abs(position.x - point.x)) {
nonPrise = false;
}
}
}
return nonPrise;
}
}
And below is the code in C++:
#include <iostream>
#include <list>
#include <math.h>
#include <stdlib.h>
using namespace std;
// Class to represent points.
class Point {
private:
double xval, yval;
public:
// Constructor uses default arguments to allow calling with zero, one,
// or two values.
Point(double x = 0.0, double y = 0.0) {
xval = x;
yval = y;
}
// Extractors.
double x() { return xval; }
double y() { return yval; }
};
#define LARGEUR_GRILLE 22
list<Point> positions;
bool verifierNonPrise(Point emplacement) {
bool nonPrise = true;
for (list<Point>::iterator it = positions.begin(); it!= positions.end(); it++) {
if (it->x() != emplacement.x()) {
if (it->y() == emplacement.y()) {
nonPrise = false;
}
if (abs(it->y() - emplacement.y()) == abs(it->x() - emplacement.x())) {
nonPrise = false;
}
}
}
return nonPrise;
}
bool placerDame(int i) {
bool bonnePosition = false;
for (int j = 1; j <= LARGEUR_GRILLE && !bonnePosition; j++) {
Point emplacement(i,j);
positions.push_back(emplacement);
if (verifierNonPrise(emplacement) && (i == LARGEUR_GRILLE || placerDame(i + 1))) {
bonnePosition = true;
}
else {
positions.pop_back();
}
}
return bonnePosition;
}
int main()
{
int i = 1;
placerDame(i);
for (list<Point>::iterator it = positions.begin(); it!= positions.end(); it++) {
cout << "(" << it->x() << "; " << it->y() << ")" << endl;
}
return 0;
}
-O3
to the command line.Point
's methods are implicitly inline. But they aren't even necessary. The data should be public.std::list
. As for the getters, these would be optimized out too if inlined, but using them could result in extra copies of the data members being made, because semantically they return values. Anyway, it is hard to see how Java could out-perform C++ in such a simple, numeric problem, if coded correctly in both languages. I wouldn't expect C++ to massively out-perform Java either.