convert String to String array [closed]

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i try to create a program to encrypt text into code with my own rule. but, i found some problems to split the text and send it to array

i want to see this in Msg array

Msg[0] = "h";
Msg[1] = "e";
Msg[2] = "l";
Msg[3] = "l";
Msg[4] = "o";

and i try to code like this

String text = "hello";
String[] Msg = new String[] {text};

this code works, but the result isn't like i want. can you help me to solve this problem

thanks..

How is it not working? What you're showing it's doing at the top appears to be what I would expect it to do. What is the result that you would like? — krillgar
– krillgar, Commented Jul 10, 2014 at 23:06
possible duplicate of string to string array conversion in java — azurefrog
– azurefrog, Commented Jul 10, 2014 at 23:08
Do you want to get array of characters? If so you can get char [] via yourString.toCharArray(). Or do you really want to get array of Strings with each character separated? — Pshemo
– Pshemo, Commented Jul 10, 2014 at 23:08

BitNinja · Accepted Answer · 2014-07-10 23:19:45Z

6

If you want to split the string up into each character then use this code:

String text = "hello";
String[] Msg = text.split("(?!^)");

This uses a regular expression to split the code by every spot that is between two characters (excluding the first blank spot).

Here's how it works:

.split(""); would be fine for splitting the string if you're using java 8 as @Pshemo pointed out. But below that you will end up with an array that starts with "" as the first element.

This regular expression avoids that because it uses a negative lookahead (?!) to make sure to not match the beginning of a line, which is represented by the ^ character.

edited Jul 10, 2014 at 23:19

answered Jul 10, 2014 at 23:07

BitNinja

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5 Comments

Pshemo Over a year ago

Any explanation of (!?^)? BTW this regex is no longer needed since Java 8, you can just use split("").

drew moore Over a year ago

please explain why this would be preferable to simply toCharArray()?

Pshemo Over a year ago

@drewmoore Different return types, this actually does exactly what OP described in example (it returns String[], not char[]).

BitNinja Over a year ago

@drewmoore Because the OP requests that the array be of String.

drew moore Over a year ago

indeed he does. i'm sorry, i misread the question..

dan.m was user2321368 · Accepted Answer · 2014-07-10 23:07:37Z

4

char[] String.toCharArray() is probably what you are looking for.

See: http://docs.oracle.com/javase/7/docs/api/java/lang/String.html#toCharArray()

answered Jul 10, 2014 at 23:07

dan.m was user2321368

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2 Comments

SirDarius Over a year ago

The desired output indicates that Msg is a string[] and not a char[]. Why would someone do that, I don't know, but I'm afraid this does not answer the question.

dan.m was user2321368 Over a year ago

Sometimes the asker doesn't really know what they want. Hence the "is probably what you are looking for". @BitNinja's answer above is the solution if the OP's question was exactly what he was asking for.

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