How do I sort a list of Doubles in Scala? [duplicate]

Question

How do I sort a simple list of Doubles in Scala?

var dubs = List(1.3,4.5,2.3,3.2)

I think my question may not have accurately reflected my specific problem, since I realize now that dubs.sorted will work just fine for the above. My problem is as follows, I have a string of doubles "2.3 32.4 54.2 1.33" that I'm parsing and adding to a list

var numsAsStrings = l.split("\\s");
var x = List(Double);
var i = 0;
for( i <- 0 until numsAsStrings.length) {
  x :+ numsAsStrings(i).toDouble;
}

So, I would think that I could just call x.sorted on the above, but that doesn't work... I've been looking over the sortBy, sorted, and sortWith documentation and various posts, but I thought the solution should be simpler. I think I'm missing something basic, regardless.

possible duplicate of How do I sort an array in Scala? Another dupe or close to: stackoverflow.com/questions/9751434/… — Paul Sasik
– Paul Sasik, Commented Jul 4, 2014 at 20:44
I don't think you can honestly say you've researched this question before posting. — Michael Zajac
– Michael Zajac, Commented Jul 4, 2014 at 20:45
@LimbSoup. You're right in a way, especially given what I originally posted. I didn't accurately reflect my problem, though, which is my fault. dubs.sorted works just fine on what I listed as the first example. My problem may be equally trivial, but I can seem to find the easy solution I expected. I'v added more detail to the original question — Gary Sharpe
– Gary Sharpe, Commented Jul 4, 2014 at 20:54
List(Double) should be List[Double](). List(Double) is a list holding the companion object for Double. — wingedsubmariner
– wingedsubmariner, Commented Jul 5, 2014 at 2:39

dhg · Accepted Answer · 2014-07-04 20:44:59Z

2

Use the sorted method

dubs.sorted  // List(1.3, 2.3, 3.2, 4.5)

answered Jul 4, 2014 at 20:44

dhg

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1 Comment

Gary Sharpe Over a year ago

Thank you for answering the original question. This has become a bit of a cluster @#$%, since I believe my problem has more to do with lists than sorting...

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