Why does parseJSON wrap my JavaScript object in a new object?

Question

Consider this JavaScript object wrapped as JSON:

vars = $.parseJSON('{"timestamp":1402720347,"AktiveSprak":{"en":{"ID":"en","Norsk_navn":"Engelsk","Lokalt_navn":"English","Bilde":"flagg_en.png","Aktivt":"1"},"no":{"ID":"no","Norsk_navn":"Norsk","Lokalt_navn":"Norsk","Bilde":"flagg_no.png","Aktivt":"1"}}}')

I want to iterate over the object AktiveSprak, but I can’t figure out how.

Now I can do vars.AktiveSprak but in order to use jQuery's .each function the object needs to be wrapped in jQuery like this $(vars). Now, why can't I do any of these:

$(vars).AktiveSprak.each(function(){})
$(vars)[0].AktiveSprak.each(function(){})
$(vars).find("AktiveSprak").each(function(){})
$(vars)[0].find("AktiveSprak").each(function(){})

Why are you trying to use $(vars) at all? Your vars is already a reference to the object, so you can say vars.AktiveSprak. — nnnnnn
– nnnnnn, Commented Jun 14, 2014 at 5:48

Exlord · Accepted Answer · 2014-06-14 05:11:58Z

6

$(object).each can only be called on jquery objects to use with normal objects :

$.each(vars.AktiveSprak,function(index,item){});

http://api.jquery.com/jquery.each/

The $.each() function is not the same as $(selector).each(), which is used to iterate, exclusively, over a jQuery object. The $.each() function can be used to iterate over any collection, whether it is an object or an array.

answered Jun 14, 2014 at 5:11

Exlord

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rplantiko · Accepted Answer · 2014-06-14 05:23:31Z

1

Even when using jQuery, not every iteration must be performed with $.each. In this case, better use JavaScript's built-in in iterator

var s = $.parseJSON('{"timestamp":..., "AktiveSprak":{ "de":..., "no":... }}');
for (var lang in s.AktiveSprak) { 
  console.log( lang ); 
  }

answered Jun 14, 2014 at 5:23

rplantiko

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