Arguments of variable number of integers in method in java

Question

Question: Write a method that takes as input a variable number of integers. The method should return the average of the integers as a double. Write a full program to test the method.

That code below creates an array of 10 integers and finds their average. However, I need it to create a variable number of arguments (int...a) where any number of integers entered can be averaged. Can someone help me.Thanks.

My code:

package average.pkgint;
import java.util.Scanner;
public class AverageInt {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        int [] number = new int [10];
        Scanner b = new Scanner(System.in);
        System.out.println("Enter your 10 numbers:");
        for (int i = 0; i < number.length; i++) {
             number[i] =  b.nextInt() ;

        }

        System.out.println("The average is:"+Avnt(number));

    }

    public static int  Avnt(int [] a){//declare arrays of ints
        int result = 1;      
        int sum = 0;
        //iterate through array
        for (int num : a) {
              sum += num; 
        }
            double average = ( sum / a.length);//calculate average of elements in array
            result = (int)average;

             return result;

    }

    }

Don't use int as type of sum. You can make that overflow with just 2 ints (Integer.MAX_VALUE + 1 == Integer.MIN_VALUE). Use long or double instead. — fabian
– fabian, Commented Jun 8, 2014 at 13:30

Arash Saidi · Accepted Answer · 2014-06-08 13:19:27Z

1

This is a way of getting as many variables as you want to a method and going through them all:

public static void testVarArgs(int... numbers){
    for(double u: numbers) {
        System.out.println(u);
    }
}

answered Jun 8, 2014 at 13:19

Arash Saidi

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Alexandru Cimpanu · Accepted Answer · 2014-06-08 13:28:01Z

0

If you don't want to read the number of integers as the first input you can declare a stack in stead of an array

Stack<Integer> numbers=new Stack<>()

and then you can add the numbers with the add method.

answered Jun 8, 2014 at 13:28

Alexandru Cimpanu

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3 Comments

Alexandru Cimpanu Over a year ago

Thanks for the heads-up. I was working at something with an array of stacks and forgot to change the left part.

user247322 Over a year ago

it does but the question said " Write a method that takes as input a VARIABLE number of integers". the program takes only 10. want to rewrite using the (int...a) syntax.

Alexandru Cimpanu Over a year ago

You just add them as a stack and when you call the int...a method you make a conversion from stack to array.

Edwin Torres · Accepted Answer · 2014-06-08 13:47:59Z

0

Just change your method declaration to a variable length parameter:

public static int  Avnt(int ... a){//declare variable int arguments

When you use a variable length parameter, you supply the values in the method invocation. For example,

    System.out.println(Avnt(1,2,3));
    System.out.println(Avnt(1,2,3,4,5,6,9,9,9,10,10));

Actually, this looks like it meets your requirements. Just add method calls in your main() similar to these.

edited Jun 8, 2014 at 13:47

answered Jun 8, 2014 at 13:22

Edwin Torres

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4 Comments

user247322 Over a year ago

How would I re-write this program then. Do I still need to loop through the array in main. Also, since it would now be a variable number of arguments do I still need to set the array size.

Edwin Torres Over a year ago

Leave your method as is. "a" will become an array inside your method. All you need to do is change the declaration as above.

user247322 Over a year ago

Thanks..but the number of integers I can average is still limited to 10 since that's the size of my array in main. How do I make it unlimited?

Edwin Torres Over a year ago

See the System.out.println() statements above.

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