regex to extract string part

Question

i have this string :

Le serveur a retourné une erreur "500 An exception occurred while executing 'select DIVISIONTEST(4,0) from dual': SQLSTATE[HY000]: General error: 20000 OCIStmtExecute: ORA-20000: Bien essayé! ORA-06512: à "FOO.DIVISIONTEST", line 8 (ext\pdo_oci\oci_statement.c:148)".

i would like to show only this part : Bien essayé! nothing before or after this part.

This string is generated by a:

$exception->getMessage()

Can you help me with a regex ? thanks you

EDIT : sorry , the customized message will change. I should have been more precise. I'm looking for a way to get the message after ORA-20000: and before the ORA: following . I'm trying to get exception raised from a PL/SQL request. The error raised is a customized message

Answer 1

Well since you only want to match one case, you could use: preg_match
See PHP Manual: https://www.php.net/preg_match

Example:

$subject = $exception->getMessage();
$pattern = '/Bien essayé!/';
preg_match($pattern, $subject, $matches, PREG_OFFSET_CAPTURE);
print_r($matches);

Answer 2

Edit: updated after original post changed:

$re = '/OCIStmtExecute: ORA-[0-9]+: (.+) ORA-[0-9]+:/'; 
$subject = $exception->getMessage();

preg_match($re, $subject, $matches);
print_r($matches);

Answer 3

<?php 
if (preg_match("/Bien essayé!/i",$exception->getMessage())
   echo : "Bien essayé!";
else
   echo "Pas bien essayé :-D ";
?>