regular expression that matches the below pattern

Question

I'm not good in regular expression, but today I faced an unavoidable situation, So I need a regular expression that matches the case below:

|hhas.jpg||sd22-9393das.png||8jjas.png||IMG00338-20110109.jpg|

I tried this regex : /(?<=\|)(\w|\d+\.\w+)(?=\|)/i but not getting the desired results...

I want to match all the strings by using preg_match function of PHP between two | signs ie hhas.jpg, sd22-9393das.png etc...

wHEN I TRIED THIS /(?<=\|).+(?=\|)/i ,I GET Array ( [0] => b2.png||b3.jpg||b5.jpg — Arun Wilson
– Arun Wilson, Commented May 2, 2014 at 5:26
What I need is Array ([0]=>hhas.jpg [1]=>sd22-9393das.png [2]=>8jjas.png[3]=>IMG00338-20110109.jpg — Arun Wilson
– Arun Wilson, Commented May 2, 2014 at 5:29
@user3041943 I would just split using preg_split() with ~\|+~. After that you only need to get rid of empty values. — HamZa
– HamZa, Commented May 2, 2014 at 8:19

sshashank124 · Accepted Answer · 2014-05-02 05:26:17Z

2

You can use the following regex:

/\|([^|]*)\|/gi

Demo

Matched strings:

1. hhas.jpg
2. sd22-9393das.png
3. 8jjas.png
4. IMG00338-20110109.jpg

answered May 2, 2014 at 5:26

sshashank124

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Comments

Shankar Narayana Damodaran · Accepted Answer · 2014-05-02 05:31:36Z

2

Use this..

preg_match_all('/\|(.*?)\||/', $str, $matches);
print_r(array_filter($matches[1]));

OUTPUT :

Array
(
    [0] => hhas.jpg
    [1] => sd22-9393das.png
    [2] => 8jjas.png
    [3] => IMG00338-20110109.jpg
)

Demonstration

enter image description here

edited May 2, 2014 at 5:31

answered May 2, 2014 at 5:25

Shankar Narayana Damodaran

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Comments

aelor · Accepted Answer · 2014-05-02 05:30:57Z

your expression :

/(?<=\|)(\w|\d+\.\w+)(?=\|)/i

pretty well written , but just has a few minor flaws

when you say \w that is only one character.
the OR condition
\d+\.\w+ will match only when it meets the same order. i.e. list of digits first followed by a . and then followed by letters or digits or underscore.

better change your regex to :

/(?<=\|)(.*?)(?=\|)/ig

this will give you anything which is between |s

also IMHO , using lookarounds for such a problem is an overkill. Better use :

/\|(.*?)\|/ig

Mohan · Accepted Answer · 2014-05-02 05:35:02Z

1

Try without using regular expression.

explode('||', rtrim(ltrim ('|hhas.jpg||sd22-9393das.png||8jjas.png||IMG00338-20110109.jpg|','|'),'|'));

Output:

Array ( [0] => hhas.jpg [1] => sd22-9393das.png [2] => 8jjas.png [3] => IMG00338-20110109.jpg )

answered May 2, 2014 at 5:35

Mohan

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1 Comment

martijnn2008 Over a year ago

That would not suffice for the case '|a||b||c|d|e|', but I don't know if the OP needs to handle those cases aswell.

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