unset an array with a specfic condition

Question

Basically I have this array $code:

Array
(
    [1] => Array
        (
            [0] => FRANCE
            [1] => 26422
            [2] => 61748
            [3] => 698477678
        )

    [2] => Array
        (
            [0] => UNITED STATES
            [1] => 545
            [2] => 2648
            [3] => 55697455
        )

    [3] => Array
        (
            [0] => CANADA
            [1] => 502
            [2] => 1636
            [3] => 15100396
        )
    [4] => Array
        (
            [0] => GREECE
            [1] => 0
            [2] => 45
            [3] => 458
        )

I want to unset all the countries with $code[$key][1] == 0 so I tired this:

$code = array_filter($code, function (array $element) {
return !preg_match('(0)i', $element[1]);
});

But it returns all the countries unless the one that has in $code[$key][1] 0, Like this:

Array
(
    [1] => Array
        (
            [0] => FRANCE
            [1] => 26422
            [2] => 61748
            [3] => 698477678
        )

    [2] => Array
        (
            [0] => UNITED STATES
            [1] => 545
            [2] => 2648
            [3] => 55697455
        )

Any how I can achieve this? Thanks!

Why using preg. In this way you are filtering all countries which code contains 0. Use simple == instead — Maxim Krizhanovsky
– Maxim Krizhanovsky, Commented Apr 14, 2014 at 16:44
Why not just return $element[1] !== 0;? (or return $element[1] !== "0"; in case of a string). In your sample data this will remove only GREECE. The regular expression would ^0$ but don't use regular expressions here. — Halcyon
– Halcyon, Commented Apr 14, 2014 at 16:44

Sharanya Dutta · Accepted Answer · 2014-04-14 17:04:40Z

2

Without regex:

$code = array_filter($code, function (array $element) {
return ($element[1] !== 0);
});

With regex (you need to use anchors):

$code = array_filter($code, function (array $element) {
return !preg_match('/^0$/', $element[1]);
});

However, I’ll recommend a simple foreach loop instead of array_filter:

foreach($code as $key => $val){
    if($val[1] === 0) unset($code[$key]);
}

edited Apr 14, 2014 at 17:04

answered Apr 14, 2014 at 16:49

Sharanya Dutta

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3 Comments

Amal Over a year ago

+1. Anyway ,preg_match() isn't required for this task. The first one should do it. I would change it to $element[1] !== 0;, though :)

Sharanya Dutta Over a year ago

@AmalMurali I’ve given the regex solution simply in order to show what went wrong with the original attempt by the author of the question. And I’ve made the change that you’ve suggested here. Thank you very much.

Amal Over a year ago

I know, @Sharanya. That was just meant to be an "FYI" comment for future readers. I see you've added a foreach solution as well. That's the best one to use here, IMO.

user3528035 · Accepted Answer · 2014-04-14 16:50:11Z

1

If I understand, you are trying to remove only Greece, it should be as simple as:

$code = array_filter($code, function (array $element) {
    return $element[1] != 0
});

The regular expression you are using will remove every country where the key has a 0 in the value, that will exclude also 502 in your example.

answered Apr 14, 2014 at 16:50

user3528035

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