A more elegant way to copy std::string into a vector<char> [duplicate]

Question

I can't see to find the answer to this, so sorry in advance if there is a duplicate.

Is there a more elegent way of creating a `vector<char>` from a `string`.

std::string s("I'm afraid. I'm afraid, Dave.");
std::vector<char> temp;                        
for (size_t x = 0; x < s.size(); x++)          
{                                              
    temp.push_back(s[x]);                      
}

Thanks

David G · Accepted Answer · 2014-04-06 16:20:12Z

7

Construct a range with an iterator like this:

std::vector<char> temp(s.begin(), s.end());

answered Apr 6, 2014 at 16:20

David G

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Manu343726 · Accepted Answer · 2014-04-06 16:20:20Z

0

Use std::copy():

std::copy( std::begin( string ) , std::end( string ) , std::back_inserter<char>( vector ) );

Or use the overload of the std::vector ctor which takes a range to be initializated with:

std::vector<char> vector{ std::begin( string ) , std::end( string ) };

answered Apr 6, 2014 at 16:20

Manu343726

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humam · Accepted Answer · 2014-04-06 16:29:31Z

0

You can try the following:

std::string str = "I'm afraid. I'm afraid, Dave.";
std::vector<char> data(str.begin(), str.end());

answered Apr 6, 2014 at 16:29

humam

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A more elegant way to copy std::string into a vector<char> [duplicate]

Is there a more elegent way of creating a `vector<char>` from a `string`.

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Is there a more elegent way of creating a vector<char> from a string.

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Is there a more elegent way of creating a `vector<char>` from a `string`.