How to pass array arguments and something else?

Question

$cmd = {
    param([System.Array]$filestocopy = $(throw "need files"),
    [bool]$copyxml)
    if($copy)
        #do stuff
}
$files = @("one","two","three")

invoke-command -session $s -scriptblock $cmd -argumentlist (,$files) $copyxml

Error:

Invoke-Command : A positional parameter cannot be found that accepts argument 'True'.

I have searched high and low and cannot find how to pass in an array along with something in a argumentlist. I have tried: (,$files,$copyxml), (,$files),$copyxml, and (,$files) $copyxml

Is there a way to do this?

Ansgar Wiechers · Accepted Answer · 2014-03-20 18:53:44Z

3

The argument to the parameter -ArgumentList must be an array, otherwise $copyxml will be interpreted as the next positional parameter to Invoke-Command. Also, passing the array in a subexpression ((,$files)) will cause it to be mangled. Simply passing the variable ($files) is sufficient. Change this:

invoke-command -session $s -scriptblock $cmd -argumentlist (,$files) $copyxml

into this:

invoke-command -session $s -scriptblock $cmd -argumentlist $files,$copyxml

edited Mar 20, 2014 at 18:53

answered Mar 20, 2014 at 16:40

Ansgar Wiechers

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4 Comments

TheMadTechnician Over a year ago

Since $files is already an array you shouldn't need the (,$files),$copyxml and should be able to just do $files,$copyxml

stewart99 Over a year ago

So now when I do a foreach($f in $filestocopy), $f = "fileone filetwo filethree". What happened?

Ansgar Wiechers Over a year ago

@TheMadTechnician You're right. (,$files) doesn't do what the OP wants, because the subexpression mangles the array before passing it into the function.

stewart99 Over a year ago

I thought I had tried $files,$copyxml once, but I guess I didn't. That worked, as expected.

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