Python User Input Average

Question

I'm trying to work on a school assignment that asks the user to input 3 integers, then I need to pass these three integers as parameters to a function named avg that will return the average of these three integers as a float value.

Here's what I've come up with so far, but I get this error:

line 13, in <module>
    print (average)
NameError: name 'average' is not defined

Advice?

    a = float(input("Enter the first number: "))
    b = float(input("Enter the second number: "))
    c = float(input("Enter the third number: "))

    def avg(a,b,c):
        average = (a + b + c)/3.0
        return average


    print ("The average is: ")
    print (average)

    avg()

"print" is a statement, not a function. You should not use parenthesis around what you want to print. — jrennie
– jrennie, Commented Mar 14, 2014 at 2:22
@jrennie OP did not specify if this was Python 2.x or 3.x, but if this is Python 3, print is indeed a function and requires parentheses — Cory Kramer
– Cory Kramer, Commented Mar 14, 2014 at 13:02

Cory Kramer · Accepted Answer · 2014-03-14 01:19:54Z

1

average only exists as a local variable inside the function avg

def avg(a,b,c):
    average = (a + b + c)/3.0
    return average

answer = avg(a,b,c) # this calls the function and assigns it to answer

print ("The average is: ")
print (answer)

answered Mar 14, 2014 at 1:19

Cory Kramer

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1 Comment

CoPoPHP Over a year ago

I can see where I went wrong with not passing the variables. Thanks!

Matt Woelk · Accepted Answer · 2014-03-14 01:20:51Z

0

You should print(avg(a,b,c)) because the average variable is only stored in the function and cannot be used outside of it.

answered Mar 14, 2014 at 1:20

Matt Woelk

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Comments

OneOfOne · Accepted Answer · 2014-03-14 01:21:07Z

0

You called avg without passing variables to it.
You printed average which is only defined inside the avg function.
You called avg after your print.

Change print (average) to

average = avg(a, b, c);
print(average)

answered Mar 14, 2014 at 1:21

OneOfOne

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