How to extract signature from function reference in Python?

Question

Let's say I have a function in Python like so:

def foo(x): pass

According to Python, 'foo' alone is a function reference, right?

>>> def foo(x): pass
...
>>> foo
<function foo at 0xb7f3d1b4>

Is there any way I can examine the function reference to determine the number of arguments it expects?

BTW, I see that there's a PEP related to this: python.org/dev/peps/pep-0362 — Stephen Gross
– Stephen Gross, Commented Feb 8, 2010 at 19:56

SilentGhost · Accepted Answer · 2010-02-08 20:03:39Z

4

You need inspect.getfullargspec in py3k or inspect.getargspec in earlier versions.

 >>> def foo(x): pass

>>> import inspect
>>> inspect.getfullargspec(foo)
FullArgSpec(args=['x'], varargs=None, varkw=None, defaults=None, kwonlyargs=[], kwonlydefaults=None, annotations={})

edited Feb 8, 2010 at 20:03

answered Feb 8, 2010 at 19:57

SilentGhost

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