You don't want to do that in shell script.
Try this. Create a file named "hello.py" and put the following code in the file (assuming you are on unix system):
#!/usr/bin/env python
print "Hello World"
and in your shell script, write something lke this
#!/bin/sh
python hello.py
and you should see Hello World in the terminal.
That's how you should invoke a script in shell/bash.
To the main question: how do you pass arguments?
Take this simple example:
#!/usr/bin/env python
import sys
def hello(name):
print "Hello, " + name
if __name__ == "__main__":
if len(sys.argv) > 1:
hello(sys.argv[1])
else:
raise SystemExit("usage: python hello.py <name>")
We expect the len of the argument to be at least two. Like shell programming, the first one (index 0) is always the file name.
Now modify the shell script to include the second argument (name) and see what happen.
haven't tested my code yet but conceptually that's how you should go about
edit:
If you just have a line or two simple python code, sure, -c works fine and is neat. But if you need more complex logic, please put the code into a module (.py file).