I have a problem When I want To rebuild my array . this is I am create on phpfiddle.org
http://phpfiddle.org/main/code/tzp-t1u
anyone can give me suggestion ?
6
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1You may need to provide a little more information; - what are the rules around merging the arrays (is there a common key, is there a value that match?) - are there always just 3 indexes to start with, etc.roycable– roycable2014-02-21 04:33:22 +00:00Commented Feb 21, 2014 at 4:33
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you would have to iterate throw the array. Array merge doesn't merge values of existing keys. it just mergers two array together and leaves duplicate keys untouchedKrimson– Krimson2014-02-21 04:34:34 +00:00Commented Feb 21, 2014 at 4:34
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Post your array generating code with few sample array, I really can't get what is your output & what you want it to be.Ankit Pise– Ankit Pise2014-02-21 04:35:34 +00:00Commented Feb 21, 2014 at 4:35
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I am updated my questionviyancs– viyancs2014-02-21 04:50:22 +00:00Commented Feb 21, 2014 at 4:50
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What is your matching criteria for the arrays, how do you group the child key?Nouphal.M– Nouphal.M2014-02-21 05:00:15 +00:00Commented Feb 21, 2014 at 5:00
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1 Answer
This code will help you
<?php
$result = array (
array(
'lev1'=> null,
'lev2'=> 34,
'lev3'=> 21,
'lev4'=> 22,
'child' => 'cyaiooo'
),
array(
'lev1'=> null,
'lev2'=> 34,
'lev3'=> 10,
'lev4'=> 8,
'child' => 'test1'
),
array(
'lev1'=> null,
'lev2'=> 34,
'lev3'=> 21,
'lev4'=> 22,
'child' => 'hodem'
)
);
$data = array();
foreach($result as $value)
{
if(count($data)==0)
{
$data[] = $value;
}else{
foreach($data as &$container)
{
if($value['lev1']==$container['lev1']
&&
$value['lev2']==$container['lev2']
&&
$value['lev3']==$container['lev3']
&&
$value['lev4']==$container['lev4'])
{
if(is_string($container['child']))
{
//get the string value
$string = $container['child'];
//unset the child string
unset($container['child']);
//declatre the array
$container['child'] = array();
$container['child'][] = $string;
}
$container['child'][] = $value['child'];
break;
}else{
$data[] = $value;
break;
}
}
}
}
print_r($data);
