Alphabetical Sorting Array [duplicate]

Question

I used following function for sorting array.

var trArr = [{'Abc', 1}, {'ACd', 3}, {'Aab', 4}];

function compare(a,b) {
          if (a.name > b.name)
          {
              return -1;
          }
          if (a.name < b.name)
          {
              return 1;
          }

          return 0;
}

trArr.sort(compare);

result:

[{'ACd', 3}, {'Aab', 4}, {'Abc', 1}];

above result is due to capital 'C'

I need the following result:

[{'Aab', 4}, {'Abc', 1}, {'ACd', 3}];

.name.toLowerCase()

user1636522
– user1636522

2014-02-06 18:22:24 +00:00
Commented Feb 6, 2014 at 18:22 — user1636522
– user1636522, Commented Feb 6, 2014 at 18:22

Satpal · Accepted Answer · 2014-02-06 18:26:12Z

1

Try this

var trArr = [{
    name: 'Abc',
    id: 1
}, {
    name: 'ACd',
    id: 3
}, {
    name: 'Aab',
    id: 4
}];

function compare(a, b) {
    if (a.name.toLowerCase() < b.name.toLowerCase()) {
        return -1;
    }
    if (a.name.toLowerCase() > b.name.toLowerCase()) {
        return 1;
    }
    return 0;
}

trArr.sort(compare);
console.log(trArr)

DEMO

answered Feb 6, 2014 at 18:26

Satpal

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Comments

beautifulcoder · Accepted Answer · 2014-02-06 18:24:48Z

0

Try using toLowerCase

function compare(a, b) {
    if (a.name.toLowerCase() > b.name.toLowerCase()) {
        return -1;
    }
    if (a.name.toLowerCase() < b.name.toLowerCase()) {
        return 1;
    }
    return 0;
}

edited Feb 6, 2014 at 18:24

user1636522

answered Feb 6, 2014 at 18:23

beautifulcoder

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