python get class name from object

Question

I am trying to return a version number, with a way to implement exceptions.

Since the exceptions can be for any of my classes I am trying to get the classname from the object.

Problem is, I get a tuple instead of a string:

def version_control(*args):
    version = 1.0
    print args
    #Exception example:
    print str(args.__class__.__name__)
    if 'User' == args.__class__.__name__:
        version = 12.3

    return version

How can I change the str(args.__class__.__name__) in such a way that it return the name of the class as string?

No, you are not getting a tuple from args.__class__.__name__; something else is wrong. And why not use if isinstance(args, User): instead? — Martijn Pieters
– Martijn Pieters, Commented Jan 4, 2014 at 13:56

Eric · Accepted Answer · 2014-01-04 13:56:50Z

5

I get a tuple instead of a string

No, you get the string "tuple" instead of some other string, because args is a tuple of arguments.

When you call version_control(obj, 1, 2), args == (obj, 1, 2). You want to be looking at args[0], which in this example is obj

answered Jan 4, 2014 at 13:56

Eric

98.1k54 gold badges257 silver badges389 bronze badges

Sign up to request clarification or add additional context in comments.

5 Comments

Hans de Jong Over a year ago

Excuse me first time working with args, i guess i can solv this easier with kwargs then?

Martijn Pieters Over a year ago

@HansdeJong: why would keyword arguments solve the problem? Your function is being called with positional arguments; just index the args tuple. How many different ways is this function being called?

Hans de Jong Over a year ago

i want to be able to put any of my objects (from most of my classes) in this and only give an exception version when an object is passed that is in the exception list pastebin.com/NGDHTN68 this seems to work fine

Martijn Pieters Over a year ago

Sure, but since you didn't show us how the function is being called, we cannot help you with what arguments are being passed in either.

Hans de Jong Over a year ago

My excuses for that, still pretty new to django, python and stackoverflow. Next time i try to be more precise

kingsfoil · Accepted Answer · 2022-04-07 02:44:50Z

3

To get the class name as a string:

f = Foo()
f.__class__.__name__ # => 'Foo'

However, consider using `isinstance()` instead:

isinstance(f, Foo) # => True

This is more readable and covers a majority of use cases, and should be preferred when using a conditional.

edited Apr 7, 2022 at 2:44

answered Mar 30, 2022 at 22:42

kingsfoil

3,8957 gold badges37 silver badges60 bronze badges

2 Comments

kingsfoil Over a year ago

Adding this answer here to provide a condensed tl;dr that directly addresses the question title, for users who googled 'python get classname from object' or something similar.

kingsfoil Over a year ago

Credit to the comment on the question by Martijn Peters, which contains this information as well.

Collectives™ on Stack Overflow

python get class name from object

2 Answers 2

5 Comments

To get the class name as a string:

However, consider using `isinstance()` instead:

2 Comments

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

5 Comments

To get the class name as a string:

However, consider using isinstance() instead:

2 Comments

Related

However, consider using `isinstance()` instead: