#include "stdafx.h"
#include <iostream>
#include <vector>
#include <string>
class Helper
{
public:
Helper() { init(); }
virtual void print() {
int nSize = m_vItems.size();
std::cout << "Size : " << nSize << std::endl;
std::cout << "Items: " << std::endl;
for(int i=0; i<nSize; i++) {
std::cout << m_vItems[i] << std::endl;
}
}
protected:
virtual void init() { m_vItems.push_back("A"); }
std::vector<std::string> m_vItems;
};
class ItemsHelper : public Helper
{
public:
ItemsHelper() { }
protected:
virtual void init() {
Helper::init();
m_vItems.push_back("B");
}
};
int _tmain(int argc, _TCHAR* argv[]) {
ItemsHelper h;
h.print();
}
This output's that the size of the vector is 1. I expected the size to be 2 because in the ItemsHelper::init function I called the base class Helper::init() function, then I add a second item to the vector. The problem is, the ItemsHelper::init doesn't get called, the base class init function gets called instead.
I want the ItemsHelper::init function to get called, and I can do that by calling the init function in the ItemsHelper ctor rather than in the base class. BUT, the question is, is there a better way to achieve that and still keep the call to the init() in the base class? Because what if I want to create a Helper object instead of a ItemsHelper, then the init function would never get called.
btw, this is a simplified version of a issue I'm seeing in a much larger object, I just made these objects up for example.
